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V125BC [204]
2 years ago
6

Do all forms of radioactive decay change the identity of the original element?

Chemistry
1 answer:
hoa [83]2 years ago
5 0

Explanation:

<h3>yes, Radioactive decay involves the emission of a particle and/or energy as one atom changes into another. In most instances, the atom changes its identity to become a new element.</h3>

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Find the mistake in this equation:
Lisa [10]

Answer:

Explanation:

It should be

2HCl + Mg --->  MgCl2 + H2

5 0
3 years ago
Please help me please ​
german

Answer:

Sugar solution seperation method is Distillation

iron power and sand separation method is Magnetic separation

Petrol and diesel separation method is Fractional Distillation

Camphor and glass powder seperation method is Sublimation

I hope this will have you

have a great day

3 0
3 years ago
Which statement best describes a solution?
lara31 [8.8K]

A mixture having a uniform composition where the components can't be seen separately and all components are in the same state best describes a solution.

 

<span>In chemistry, a </span>solution<span> is a homogeneous mixture composed of two or more substances. In such a mixture, a solute is a substance dissolved in another substance, known as a solvent.</span>

 

The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

6 0
4 years ago
Read 2 more answers
What is the concentration of a solution made by dissolving 0.99mol of acetic acid in enough water to make 0.58L of solution?
marissa [1.9K]

Answer:

[CH₃COOH] = 1.70 M

Explanation:

When we talk about concentration we can determine Molarity

Molarity determines the moles of solute that are contained in 1L of solution.

In this case our solute is the acetic acid.

M = mol/L

M = 0.99 mol /0.58L → 1.70 M

We can also make a rule of three

In 0.58 L of solution we have 0.99 moles of solute

In 1 L of solution we may have (1 . 0.99) / 0.58 = 1.70 moles

Acetic acid is a weak acid, partially dissociated in water.

CH₃COOH  +  H₂O  ⇄  CH₃COO⁻  +  H₃O⁺     Ka

4 0
3 years ago
Consider the reaction: CO2(g) + CCl4(g) ⇌ 2 COCl2(g) ΔG° = 46.9 kJ Under the following conditions at 25 oC: LaTeX: P_{CO_2}P C O
Mamont248 [21]

Answer : The value of \Delta G_{rxn} is, -47.0kJ/mole

Explanation :

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln K_p   ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction

\Delta G_^o =  standard Gibbs free energy  = 46.9 kJ

R = gas constant = 8.314 J/mole.K

T = temperature = 25^oC=273+25=298K

K_p = equilibrium constant

First we have to calculate the value of K_p.

The given balanced chemical reaction is,

CO_2(g)+CCl_4(g)\rightarrow 2COCl_2(g)

The expression for reaction quotient will be :

K_p=\frac{(p_{COCl_2})^2}{(p_{CO_2})\times (p_{CCl_4})}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

K_p=\frac{(0.653)^2}{(0.459)\times (0.984)}

K_p=0.944

Now we have to calculate the value of \Delta G_{rxn} by using relation (1).

\Delta G_{rxn}=\Delta G^o+RT\ln K_p

Now put all the given values in this formula, we get:

\Delta G_{rxn}=-46.9kJ/mol+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (0.944)

\Delta G_{rxn}=-47.0kJ/mol

Therefore, the value of \Delta G_{rxn} is, -47.0kJ/mole

3 0
3 years ago
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