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Lapatulllka [165]
3 years ago
10

Find the difference 18/19 - 17/19 A. 2/19 B. 8/19 C. 1/19 D. 9/19

Chemistry
1 answer:
sineoko [7]3 years ago
5 0

Answer:

1/19

.....

.

...............................

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Think about how particles are arranged inside atoms. Please name and describe those three particles, and describe how the partic
vekshin1
Protons : positive charge , about same mass as neutrons , in the nucleus

neutrons : no charge , about the same mass as a proton , in the nucleus

electrons : negative charge , less mass than protons and neutrons , in orbitals outside of the nucleus
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3 years ago
Helppppppppppppppppppppp
alukav5142 [94]

decameters - meters: multiply by 10

meters to meters: multiply by 1

centimeters to meters: divide by 100

millimeters to meters: divide by 1000

For the rows at the bottom:

hectometer row: 100, multiply by 100, 4500

decameter row: 10, multiply by 10, 450

meter row: 1, multiply by 1, 45

decimeter row: 0.1, divide by 10, 4.5

centimeter row: 0.01, divide by 100, 0.45

im guessing theres a millimeter row at the bottom:

millimeter row: 0.001, divide by 1000, 0.045


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5 0
3 years ago
How many moles are in 4.233X 10^21
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0.00702906176 moles
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6 0
3 years ago
Water changes from a liquid to a gas in the process of evaporation. <br> true or false
Umnica [9.8K]
This it true because in the triangle of the transformation from solid, liquid, and gas
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4 0
3 years ago
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Iodine-131 is administered orally in the form of NaI(aq) as a treatment for thyroid cancer. The half-life of iodine-131 is 8.04
evablogger [386]

Answer:

16.6 mg

Explanation:

Step 1: Calculate the rate constant (k) for Iodine-131 decay

We know the half-life is t1/2 = 8.04 day. We can calculate the rate constant using the following expression.

k = ln2 / t1/2 = ln2 / 8.04 day = 0.0862 day⁻¹

Step 2: Calculate the mass of iodine after 8.52 days

Iodine-131 decays following first-order kinetics. Given the initial mass (I₀ = 34.7 mg) and the time elapsed (t = 8.52 day), we can calculate the mass of iodine-131 using the following expression.

ln I = ln I₀ - k × t

ln I = ln 34.7 - 0.0862 day⁻¹ × 8.52 day

I = 16.6 mg

8 0
3 years ago
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