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Lapatulllka [165]
3 years ago
10

Find the difference 18/19 - 17/19 A. 2/19 B. 8/19 C. 1/19 D. 9/19

Chemistry
1 answer:
sineoko [7]3 years ago
5 0

Answer:

1/19

.....

.

...............................

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What are the molality and mole fraction of solute in a 22.3 percent by mass aqueous solution of formic acid (HCOOH)?
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Answer:

Mole fraction for solute = 0.1, or 10%

Molality = 6.24 mol/kg

Explanation:

22.3% by mass → In 100 g of solution, we have  22.3 g of HCOOH

Mass of solution = 100 g

Mass of solute = 22.3 g

Mass of solvent = 100 g - 22.3g = 77.7 g

Let's convert the mass to moles

22.3 g . 1mol/ 46 g = 0.485 moles

77.7 g. 1mol / 18 g = 4.32 moles

Total moles = 4.32 moles + 0.485 moles = 4.805 moles

Xm for solute = 0.485 / 4.805 = 0.100 → 10%

Molality → mol/ kg → we convert the mass of solvent to kg

77.7 g.  1 kg / 1000g = 0.0777 kg

0.485 mol / 0.0777 kg = 6.24 m

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17. A balloon contains 4.50 X 1022 atoms of helium gas. Calculate the mass of helium in<br> grams.
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Answer:

1.08 grams

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we divide 12.1/22.4=0.54 moles

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