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3 years ago

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The stage of young adulthood in which individuals take time to find themselves is A. emerging adulthood. B. the period of role d

iffusion. C. the thirty-somethings. D. the trying twenties.

2 answers:

ruslelena [56]3 years ago

5 0

I believe the answer would be A. emerging adulthood. (teenager)

forsale [732]3 years ago

3 0

Answer:

(a) Emerging adulthood.

Explanation:

Emerging adulthood is a period between teenagers' dependence on guardians and grown-ups' long haul duties in adoration and work, and during these years, rising grown-ups center around themselves as they build up the information, abilities, and self-understanding they will requirement for grown-up life.

So the correct option is (a)

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the light from andromeda galaxy takes about 2.6 million years to reach earth. which of these statements is correct about the and

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A. it is <span>located at a distance of 2.6 million light years from earth</span>

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If a creature cats Ferrari, with an initial speed of 10 m/s, accelerate at a rate of 50 m/s/s for 3 seconds, what will it's fina

riadik2000 [5.3K]

160 m/s because you start off with 10 and go up by 50*3 which is 150 then add that with the begging speed to achieve 160m/s.

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3 years ago

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A certain copper wire has a resistance of 13.0 Ω . At some point along its length the wire was cut so that the resistance of one

alekssr [168]

Answer with Explanation:

Let r be the resistance of short piece of copper wire.

Resistance of copper wire=R= $13\Omega$

Resistance is directly proportional to length.

If a wire has greater resistance then,the wire will be greater in length.

Therefore,resistance of long piece of wire=7r

Total resistance of copper wire=Sum of resistance of two piece of wires

$r+7r=13$

$8r=13$

$r=\frac{13}{8}$ ohm

Resistance of long piece of wire= $7\times\frac{13}{8}=\frac{91}{8}\Omega$

Resistance of short piece of wire = $\frac{13}{8}\Omega$

Resistivity of wire and cross section area of wire remains same .

Let L be the total length of wire and L' be the length of short piece of wire.

We know that

$R=\frac{\rho L}{A}$ = $\frac{\rho}{A}L=KL$

$\frac{R}{L}=K$

Where K= $\frac{\rho}{A}$ =Constant

Using the formula

$\frac{13}{L}=\frac{\frac{13}{8}}{L'}$

$\frac{L'}{L}=\frac{13}{8}\times \frac{1}{13}=\frac{1}{8}$

$L'=\frac{L}{8}$

Length of short piece of wire=L'= $\frac{L}{8}$

Length of long piece of wire= $L-L'=L-\frac{L}{8}=\frac{8L-L}{8}=\frac{7}{8}L$

% of length of short piece of wire= $\frac{\frac{L}{8}}{L}\times 100=12.5%$ %

The resistance of the short piece= $\frac{13}{8}\Omega$

The resistance of the long piece= $\frac{91}{8}\Omega$

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3 years ago

A child at the top of a slide has a gravatational store of 1800j what is the childs maximum kinetic store as he slides down expl

Mrac [35]

Answer:

1800 J

Explanation:

Energy is conserved, so the maximum kinetic energy equals the change in gravitational energy.

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3 years ago

Current passes through a solution of sodium chloride. In 1.00 s, 2.68×1016Na+ ions arrive at the negative electrode and 3.92×101

Tanzania [10]

Explanation:

Given that,

Number of sodium ions at the negative electrode, $Na^+=2.68\times 10^{16}$

Number of chloride ions at the positive electrode, $Cl^-=3.92\times 10^{16}$

(a) The current flowing in the circuit is due to the positive as well as negative charges such that total charge becomes:

$Q=(Na^++Cl^-)e$

$Q=(2.68\times 10^{16}+3.92\times 10^{16})(1.6\times 10^{-19})$

Q = 0.01056 C

The current is given by :

$I=\dfrac{Q}{t}$

$I=\dfrac{0.01056}{1}=10.56\ mA$

So, the current passing between the electrodes is 10.56 mA.

(b) The direction of electric current is towards negative electrodes.

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3 years ago

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