3 years ago

HEY CAN ANYONE PLS ASNWER DIS!!!!!!!

Physics

1 answer:

noname [10]3 years ago

3 0

Answer:

5 is a solid

6. is A.

7 is A and C.

8 is I think C.

9 is evaporation

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A gasoline engine receives 200 J of energy from combustion and loses 150 J as heat to the exhaust. What is its efficiency? 75% 2

choli [55]

50/200×100%=25% is answer the formula is usefull energy output divided by total energy provided into 100%

8 0

3 years ago

Read 2 more answers

When water freezes, its volume increases by 9.05% (that is, equation). What force per unit area is water capable of exerting on

PIT_PIT [208]

Answer:

1.991 × 10^(8) N/m²

Explanation:

We are told that its volume increases by 9.05%.

Thus; (ΔV/V_o) = 9.05% = 0.0905

To find the force per unit area which is also pressure, we will use bulk modulus formula;

B = Δp(V_o/ΔV)

Making Δp the subject gives;

Δp = B(ΔV/V_o)

Now, B is bulk modulus of water with a value of 2.2 × 10^(9) N/m²

Thus;

Δp = 2.2 × 10^(9)[0.0905]

Δp = 1.991 × 10^(8) N/m²

3 0

3 years ago

Question 4 - If Angelica starts out at 30m/s, and in 16 s speeds up to 84 m/s, what is her acceleration?

Triss [41]

Answer:

C. $3.375 m/s^2$

Explanation:

The acceleration of an object can be found using the equation:

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time it takes for the velocity to change from u to v

In this problem:

u = 30 m/s is the initial velocity of Angelica

v = 84 m/s is the final velocity

t is the time

Substituting into the equation, we find the acceleration:

$a=\frac{84-30}{16}=3.375 m/s^2$

4 0

3 years ago

Acceleration usually has the symbol a. It is a vector. What is the correct way

Ghella [55]

Explanation:

a straight line under the letter

3 0

3 years ago

Two particles move along an x axis. The position of particle 1 is given by x ! 6.00t 2 # 3.00t # 2.00 (in meters and seconds); t

s344n2d4d5 [400]

Answer:

15.6m/s

Explanation:

V1= $\frac{dx}{dt}=\frac{d}{dt}(6t^{2}+3t+2)$ because the derivate of the position is the velocity

V1=12t+3

V2=20+ $\int\limits^_ {} \,$ -8t because the integral of the acceleration is the velocity

V2= $20-4t^{2}$

V1=V2 to see when the velocities of particles match

12t+3=20-4t^2

4t^2+12t-17=0 we resolve this with $\frac{-b+-(\sqrt{b^{2} -4ac} )}{2a}$

and we take the positif root

t=1.05 sec

if we evaluate the velocity (V1 or V2) the result is 15.6m/s

7 0

3 years ago