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Ghella [55]
2 years ago
7

Noise from highways is a large issue, particularly for those who live close to the highway. Engineers have come up with several

solutions to the problem. One solution can be a high vertical wall. Second, planting vegetation, like trees. Third, using a large buffer zone or open space.
Explain how trees, a high wall or buffer zones can reduce the noise from a highway that is heard at a nearby home.
Think…
· How would the noise be for someone in a home?
· How would the noise be for someone driving on the highway?
· How does the DOPPLER EFFECT fit in to this scenario?
You must write a response with a MINIMUM of 5 sentences to receive full credit.
WILL MARK AS BRAINILEST
Physics
1 answer:
kifflom [539]2 years ago
8 0
Noise from highways are a significant issue. particularly for those who live close to the highway
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A doppler effect occurs when a source of sound moves. True or False
Shtirlitz [24]
<h2>Answer: True </h2>

The <u>Doppler effect</u> refers to the change in a wave perceived frequency when the emitter of the waves, and the receiver (or observer in the case of light) move relative to each other.

In other words, it is the variation of the frequency of a wave due to the relative movement of the source of the wave with respect to its receiver.

It should be noted that this effect  bears its name in honor of the Austrian physicist <u>Christian Andreas Doppler</u>, who in 1842 proposed the existence of this effect for the case of light in the stars. Another important aspect is that the effect occurs in all waves (including light and sound). However, it is more noticeable to humans with sound waves.

4 0
2 years ago
Based on the diagram which of the following traits come before shearing teeth?
Sliva [168]

Answer:

where is the diagram

Explanation:

4 0
3 years ago
A sound source is moving at 80 m/s toward a stationary listener that is standing in still air (a) Find the wavelength of the sou
Setler [38]

Answer:

a. wavelength of the sound, \vartheta = 1.315\vartheta_{o}

b. observed frequecy, \lambda = 0.7604\lambda_{o}

Given:

speed of sound source, v_{s} = 80 m/s

speed of sound in air or vacuum, v_{a} = 343 m/s

speed of sound observed, v_{o} = 0 m/s

Solution:

From the relation:

v = \vartheta \lambda        (1)

where

v = velocity of sound

\vartheta = observed frequency of sound

\lambda = wavelength

(a) The wavelength of the sound between source and the listener is given by:

\lambda = \frac{v_{a}}{\vartheta }         (2)

(b) The observed frequency is given by:

\vartheta = \frac{v_{a}}{v_{a} - v_{s}}\vartheta_{o}

\vartheta = \frac{334}{334 - 80}\vartheta_{o}

\vartheta = 1.315\vartheta_{o}                (3)

Using eqn (2) and (3):

\lambda = \frac{334}{1.315} = \frac{1}{1.315}\frac{v_{a}}{\vartheta_{o}}

\lambda = 0.7604\lambda_{o}

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