<span>Waves that move matter back and forth are called a.transverse waves <u>b.longitudinal wave</u> c. Medium wave</span>
Answer: yes u can use a 6.75 when measuring the pencil
Answer:
The total momentum before and after collision is 72000 kg-m/s.
Explanation:
Given that,
Mass of car = 1200 kg
Velocity of car = 10 m/s
Mass of truck = 2000 kg
Velocity of truck = 30 m/s
Using conservation of momentum
The total momentum before the collision is equal to the total momentum after collision.

Where,
=mass of car
=velocity of car
=mass of truck
=velocity of truck
Put the value into the formula



Now, The total momentum before collision is



The total momentum after collision is



Hence, The total momentum before and after collision is 72000 kg-m/s.
The answer is C why because I know it is
Water evaporates at 100⁰C
So change in temperature = 100-20 = 80⁰C
Amount of water to be evaporated = 1 liter = 1L*1kg/liter = 1 kg
Specific heat of water is 1 calorie/gram ⁰C = 4.186 joule/gram =4186 J/kg
So heat required E = mcΔT = 1 * 4186 *80= 334880 J =334.88 kJ
So amount of heat require to evaporate water = 334.88 kJ