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Bezzdna [24]
3 years ago
13

In the following pair, determine whether the two represent resonance contributors of a single species or depict different substa

nces. If two structures are not resonance contributors, explain why. Select the single best answer.
N-N ≡ N: and N=N=N:
Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

They are resonance contributors

Explanation:

Resonance structures are structures that differ only in the distribution or placement of electrons.

Considering the two structures, we can easily see that the two species have the same total number of bonds and electrons differing only in the distribution of these electrons.

Hence, they are resonance contributors.

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8 0
3 years ago
3) What is the new strategy for disposing of nuclear waste? How is this strategy still dangerous?
kumpel [21]

Answer:

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4 0
2 years ago
Which is an example of making a quantitative observation?
lions [1.4K]
Measuring the surface of an oil painting and finding its dimensions 12 to be  12 inches
8 0
3 years ago
PLEASE HURRY THIS IS TIMED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
AURORKA [14]

Answer:

if i remember correctly i beleive its A  1.8 x 10^24

but im not for sure  also i think you forgot the 24

Explanation:

5 0
3 years ago
If you combine 27.1 g of a solute that has a molar mass of 27.1 g/mol with 100.0 g of a solvent, what is the molality of the res
baherus [9]

<u>Answer:</u> The molality of the solution is 0.1 m.

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute = 27.1 g

M_{solute} = Molar mass of solute = 27.1 g/mol

W_{solvent} = Mass of solvent = 100 g

Putting values in above equation, we get:

\text{Molality of solution}=\frac{27.1\times 1000}{27.1\times 100}\\\\\text{Molality of solution}=0.1m

Hence, the molality of the solution is 0.1 m.

8 0
3 years ago
Read 2 more answers
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