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Bezzdna [24]
3 years ago
13

In the following pair, determine whether the two represent resonance contributors of a single species or depict different substa

nces. If two structures are not resonance contributors, explain why. Select the single best answer.
N-N ≡ N: and N=N=N:
Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

They are resonance contributors

Explanation:

Resonance structures are structures that differ only in the distribution or placement of electrons.

Considering the two structures, we can easily see that the two species have the same total number of bonds and electrons differing only in the distribution of these electrons.

Hence, they are resonance contributors.

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How many grams of oxygen are produced when 3.0 moles of potassium chlorate decompose completely?
Elena-2011 [213]
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4 0
2 years ago
In a lab experiment 80.0 g of ammonia [NH3] and 120 g of oxygen are placed in a reaction vessel. At the end of the reaction 72.2
valentinak56 [21]

The percent yield of the reaction : 89.14%

<h3>Further explanation</h3>

Reaction of Ammonia and Oxygen in a lab :

<em>4 NH₃ (g) + 5 O₂ (g) ⇒ 4 NO(g)+ 6 H₂O(g)</em>

mass NH₃ = 80 g

mol NH₃ (MW=17 g/mol):

\dfrac{80}{17}=4.706

mass O₂ = 120 g

mol O₂(MW=32 g/mol) :

\tt \dfrac{120}{32}=3.75

Mol ratio of reactants(to find limiting reatants) :

\tt \dfrac{4.706}{4}\div \dfrac{3.75}{5}=1.1765\div 0.75\rightarrow O_2~limiting~reactant(smaller~ratio)

mol of H₂O based on O₂ as limiting reactants :

mol H₂O :

\tt \dfrac{6}{5}\times 3.75=4.5

mass H₂O :

4.5 x 18 g/mol = 81 g

The percent yield :

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{72.2}{81}\times 100\%=89.14\%

6 0
3 years ago
2. A sample of oxygen gas is placed in a rigid 1.5L glass container at STP. If the gas is
sladkih [1.3K]

The new pressure : P₂ = 1038.39 mmHg

<h3>Further explanation</h3>

Given

1.5 L container at STP

Heated to 100 °C

Required

The new pressure

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure).

So P₁ =  1 atm = 760 mmHg

T₁ = 273 K

T₂ = 100 °C+273 = 373 K

Gay Lussac's Law  

When the volume is not changed, the gas pressure is proportional to its absolute temperature  

\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

Input the value :

P₂=(P₁.T₂)/T₁

P₂=(760 x 373)/273

P₂ = 1038.39 mmHg

7 0
2 years ago
The decomposition of methanol, ch3oh(g), to form ch4(g) and o2(g) absorbs 252.8 kj of heat per mole of oxygen formed. write a ba
Svetllana [295]
The thermochemical equation is the chemical equation including the net change of enthalpy (heat).

The chemical equation for the decomposition of methanol to form methane and oxygen is:

2CH3OH --> 2CH4 + O2

The thermochemical equation is:

2CH3OH ---> 2CH4 + O2  - 252.8 kJ

Note that the heat is placed as negative at the right side because it is absorbed during the decomposition, so the environment will have 252.8 kJ less per each mole of O2 produced.

You can equivalently write:

2CH3OH + 252.8 kJ --> 2CH4 + O2
4 0
3 years ago
Compare the appearance and pH of the unfiltered and filtered polluted water. What conclusion can be made based on these observat
Goryan [66]

Answer:

The unfiltered polluted water is not clear and is yellowish in color. The filtered polluted water is clear with a little bit of yellow color. The pH readings are beyond the range in which organisms can grow. Based on these observations, I can conclude that even though water may look clean, it could actually not be clean or it can still be harmful to living things.

6 0
3 years ago
Read 2 more answers
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