Answer:
yes that is right
Explanation:
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Answer:
(a) -49.9 kJ/mol;
(b) To the right;
(c) 34.6 kJ/mol
Explanation:
(a) For this reaction, since it's at equilibrium and standard states, we know that we can apply the equation:

Substituting the given variables:

(b) Notice that this reaction is spontaneous, since
. This means reaction spontaneously proceeds to the right side. Besides, K > 1, this means products dominate over reactants, so reaction proceeds to the right.
(c) Given the expression of the formation constant, we can use the same expression to calculate the reaction quotient at non-standard conditions:
![Q_f = \frac{[Ni(NH_3)_6]^{2+}}{[Ni^{2+}][NH_3]^6} = \frac{0.010}{0.0010\cdot 0.0050^6} = 6.4\cdot 10^{14}](https://tex.z-dn.net/?f=Q_f%20%3D%20%5Cfrac%7B%5BNi%28NH_3%29_6%5D%5E%7B2%2B%7D%7D%7B%5BNi%5E%7B2%2B%7D%5D%5BNH_3%5D%5E6%7D%20%3D%20%5Cfrac%7B0.010%7D%7B0.0010%5Ccdot%200.0050%5E6%7D%20%3D%206.4%5Ccdot%2010%5E%7B14%7D)
Now, notice that
. In this case, we have an excess of the products, this means reaction will shift to the let left to restore the equilibrium.
Calculate:

Answer:
The answer is 2.107 × 10²⁴ He atoms
Explanation:
To find the number of atoms given the number moles we use the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
N = 3.5 × 6.02 × 10²³
We have the final answer as
<h3>2.107 × 10²⁴ He atoms</h3>
Hope this helps you