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Nonamiya [84]
3 years ago
14

I need help ASAP PLEASE!

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0

Answer:

Only numbers we can think of would be 0 and 1,where cube of the numbers would be equal to the number itself.

Step-by-step explanation:

But in the case of positive numbers the constraints of the question can never be met. So, we'll have to use negative numbers as

(-ve number) ^ (even number) is always a postive number and (-ve number)^(odd number) is always a negative number.

Eg:- (-2)^3= -2 *-2 *-2= -8

(-2)^2= 4

Since, negative sign can never be associated with 0. Eliminate 0 as a possible answer.

Only option left is -1. Lets test if -1 is correct or not.

(-1)^3= -1*-1*-1= -1 i.e the number itself.

(-1)^2=-1*-1=1 which isn't equal to -1.

Therefore, -1 is the solution to this problem.

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