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3 years ago

explain why if charge cannot be created or destroyed, electrically neutral objects can become electrically charged

1 answer:

5 0

Charge is actually either excessive number or electrons or shortage of them.
as you can't destroy the electron or create it - you can't destroy or create charge

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How many basic locomotor skills are there?

CaHeK987 [17]

Eight and I don’t know what else to say but for sure 8

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3 years ago

A 5.0 kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 3.0 m/s^2, find the force

Harman [31]

We know that m = 5 kg
a = 3.0 m/s^2
g = 9.8 (since not written, lets assume it's an international standard)

T - mg = ma

T = mg + ma

T = (5 . 9.8) + (5 . 3 )

T = 49 + 15

T = 64 N

Hope this helps

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3 years ago

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Can the reaction distance be a negitive?

leonid [27]

Yes. Displacement is a vector, as opposed to distance, which is a scalar. Since displacement is a vector quantity, the negative sign represents direction. As with velocity and acceleration, it just comes down to how you define your coordinate system

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3 years ago

What profession is most likely to make use of amperes and candelas? A. nurse practitioner B. marine biologist C. electrical engi

ASHA 777 [7]

Ampere is the unit for the current that passes through the circuit. Further, the word "candela" is the unit for the luminous intensity. The professional that would make use of these units are the electrical engineer. Thus, the answer is letter C.

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3 years ago

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A projectile is shot from the edge of a cliff above the ground level with initial velocity of at an angle with the horizontal. (

Xelga [282]

Answer:

t = √2y/g

Explanation:

This is a projectile launch exercise

a) The vertical velocity in the initial instants ( $v_{oy}$ = 0) zero, so let's use the equation

y = $v_{oy}$ t -1/2 g t²

y= - ½ g t²

t = √2y/g

b) Let's use this time and the horizontal displacement equation, because the constant horizontal velocity

x = vox t

x = v₀ₓ √2y/g

c) Speeds before touching the ground

vₓ = vox = constant

$v_{y}$ = $v_{oy}$ - gt

$v_{y}$ = 0 - g √2y/g

$v_{y}$ = - √2gy

tan θ = Vy / vx

θ = tan⁻¹ (vy / vx)

θ = tan⁻¹ (√2gy / vox)

d) The projectile is higher than the cliff because it is a horizontal launch

6 0

4 years ago