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Pachacha [2.7K]
3 years ago
5

Increasing excitatory signals above threshold levels for neural activation will not affect the intensity of an action potential.

This indicates that the reaction of a neuron is: (2 points)
inhibited by the myelin sheath

delayed by the refractory period

an all-or-none response

independent of the repolarization

dependent on neurotransmitter molecules
Physics
1 answer:
ahrayia [7]3 years ago
4 0

Answer:

Option C

An all-or-none response

Explanation:

Increasing excitatory signals above threshold levels for neural activation will not affect the intensity of an action potential indicates that the reaction of a neuron is an all-or-none response

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An investigation has been completed similar to the one on latent heat of fusion, where steam is bubbled through a container of w
allochka39001 [22]

Answer:

Q_a=330 cal

Q_w=6000cal

Explanation:

From the question we are told that

Mass of the aluminum container 50 g

Mass of the container and water 250 g

Mass of the water 200 g

Initial temperature of the container and water 20°C

Temperature of the steam 100°C

Final temperature of the container, water, and condensed steam 50°C

Mass of the container, water, and condensed steam 261 g

Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C

a) Heat energy on container

Generally the formula for mathematically solving heat gain

      Q_c=M_c *C_c*( \triangle T)

Therefore imputing variables we have

      Q_a=50g *0.22*50-20  

      Q_a=330 cal

b) Heat energy on water

Generally the formula for mathematically solving heat gain

       Q_w=M_w *C_w*( \triangle T)

Therefore imputing variables we have

       Q_w=200 *1* 50-204

       Q_w=6000cal

7 0
3 years ago
A 975-kg elevator accelerates upward at 0.754 m/s2, pulled by a cable of negligible mass. Find the tension force in the cable.
Zina [86]

To solve this problem we will apply the concepts of equilibrium and Newton's second law.

According to the description given, it is under constant ascending acceleration, and the balance of the forces corresponding to the tension of the rope and the weight of the elevator must be equal to said acceleration. So

\sum F = ma

T-mg = ma

Here,

T = Tension

m = Mass

g = Gravitational Acceleration

a = Acceleration (upward)

Rearranging to find T,

T = m(g+a)

T = (975)(9.8+0.754)

T= 10290.15N

Therefore the tension force in the cable is 10290.15N

7 0
4 years ago
How are mass, distance and gpe related
Gelneren [198K]

Answer:

It is direct proportionality. The greater the mass, the greater is the gravitational potential energy. The equation for GPE is : GPE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height above the ground. As you can see GPE is directly proportional to mass, and height. KT.

Explanation:

Gravitational potential energy is a function of both the mass of your system and the mass of the thing generating the gravity field around your system.

The relationship is linear, which means that if you multiply or divide one of the masses by some number but leave everything else the same, you multiply or divide the potential energy by the same number. A 3kg mass has three times the gravitation potential energy of a 1kg mass, if placed in the same location.

6 0
3 years ago
3. A pendulum with a 1.0-kg weight is set in motion from a position 0.04 m above the lowest point on the path of the weight.
gavmur [86]

Answer: K.E = 0.4 J

Explanation:

Given that:

M = 1.0 kg

h = 0.04 m

K.E = ?

According to conservative of energy

K.E = P.E

K.E = mgh

K.E = 1 × 9.81 × 0.04

K.E = 0.3924 Joule

The kinetic energy of the pendulum at the lowest point is 0.39 Joule

6 0
3 years ago
A skier of mass 60 kg is pulled up a slope by a motor-driven cable. (a) How much work is required to pull him 75 m up a 30° slop
postnew [5]

Answer:

Explanation:

Given

mass of skier=60 kg

distance traveled by skier=75 m

inclination(\theta )=30^{\circ}

speed (v)=2.4 m/s

as the skier is moving up with a constant velocity therefore net force is zero

F_{net}=0

Force applied by cable=mg\sin \theta

F=60\times 9.8\times \sin (30)=294 N

work done=F\cdot x

W=294\cdot 75=22.125 J

(b)Power=F\cdot v

P=294\cdot 2.4=705.6 W\approx 0.946 hp

5 0
3 years ago
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