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Anika [276]
3 years ago
6

Calculate the mass of a solute in a 10% salt solution if the mass is 350 grams.

Chemistry
1 answer:
Lyrx [107]3 years ago
7 0

<u>Answer:</u> The mass of a solute is 35 grams

<u>Explanation:</u>

To calculate the mass percentage of solute, we use the equation:

\text{Mass percent of solute}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

Mass percent of solute = 10 %

Mass of solution = 350 g

Putting values in above equation, we get:

10=\frac{\text{Mass of solute}}{350g}\times 100\\\\\text{Mass of solute}=\frac{10\times 350}{100}=35g

Hence, the mass of a solute is 35 grams

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Orlov [11]

Explanation:

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For example, flammability, combustion, reactivity, electronegativity etc are allchemical properties.

On the other hand, a property that does not bring any change in chemical composition of a substance is known as a physical property.

For example, shape, size, mass, density etc are all physical properties.

Thus, we can conclude that these may all be classified as chemical properties of a substance.

5 0
3 years ago
Read 2 more answers
how the various concentrations of acid will affect the amount of limestone that is dissolved from each jar.
schepotkina [342]

The explanation of the how the various concentrations of acid will affect the amount of limestone has been given below.

Effects of acid rain on limestone:-

  • When an acid combines with a carbonate, it produces carbon dioxide as a gas and forms a salt that is soluble in the carbonate and acid's water.
  • There are several gases in the atmosphere that can dissolve in precipitation such as rain and snow.
  • Some may produce acids in rain water, such as carbonic acid, sulfuric acid, and nitric acid.
  • Because the concentration is modest, the rain is not highly acidic, but it is acidic enough to react with the carbonates that make up limestone.

Thus we discussed the affects of acid rain on limestones above.

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brainly.com/question/718250

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8 0
1 year ago
3.) All matter has both physical and chemical properties. A physical property is one that does not change the chemical nature of
dexar [7]

Answer:

D

Explanation:

It would be D because you are observing the reaction and don’t change anything

8 0
2 years ago
0.32 g of a walnut is burned under an aluminum can filled with 58.1 mL of water. The water temperature in the can increases by 3
balu736 [363]

Answer:

1.8 × 10² cal

Explanation:

When 0.32 g of a walnut is burned, the heat released is absorbed by water and used to raise its temperature. We can calculate this heat (Q) using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity of water

m: mass of water

ΔT: change in the temperature

Considering the density of water is 1 g/mL, 58.1 mL = 58.1 g.

Q = c × m × ΔT

Q = (1 cal/g.°C) × 58.1 g × 3.1°C

Q = 1.8 × 10² cal

3 0
3 years ago
A 0.4322 g sample of a potassium hydroxide – lithium hydroxide mixture requires 27.10 mL of 0.3565 M HCl for its titration to th
Yuki888 [10]

The mass percent lithium hydroxide in the mixture with potassium hydroxide, calculated from the equivalence point in the titration of HCl with the mixture, is 19.0%.  

The mass percent of lithium hydroxide can be calculated with the following equation:  

\% = \frac{m_{LiOH}}{m_{t}} \times 100    (1)

Where:

m_{t} = m_{KOH} + m_{LiOH} = 0.4322 g   (2)  

We need to find the mass of LiOH.

From the titration, we can find the number of moles of the mixture since the number of moles of the acid is equal to the number of moles of the bases at the equivalence point.    

\eta_{HCl} = \eta_{LiOH} + \eta_{KOH}

0.0271 L*0.3565 \frac{mol}{L} = \eta_{LiOH} + \eta_{KOH}

\eta_{LiOH} + \eta_{KOH} = 9.66 \cdot 10^{-3} \:mol

Since mol = m/M, where M: is the molar mass and m is the mass, we have:

\frac{m_{LiOH}}{M_{LiOH}} + \frac{m_{KOH}}{M_{KOH}} = 9.66 \cdot 10^{-3} \:mol    (3)                                        

Solving equation (2) for m_{KOH} and entering into equation (3), we can find the mass of LiOH:  

\frac{m_{LiOH}}{M_{LiOH}} + \frac{0.4322 - m_{LiOH}}{M_{KOH}} = 9.66 \cdot 10^{-3} \:mol    

\frac{m_{LiOH}}{23.95 g/mol} + \frac{0.4322 g - m_{LiOH}}{56.1056 g/mol} = 9.66 \cdot 10^{-3} \:mol              

Solving for m_{LiOH}, we have:

m_{LiOH} = 0.082 g

Hence, the percent lithium hydroxide is (eq 1):

\% = \frac{0.082 g}{0.4322 g} \times 100 = 19.0 \%  

Therefore, the mass percent lithium hydroxide in the mixture is 19.0%.

Learn more about mass percent here:

  • brainly.com/question/6992535?referrer=searchResults
  • brainly.com/question/5840377?referrer=searchResults

I hope it helps you!                        

5 0
2 years ago
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