The
combustion of heptane (C7H16) in oxygen spontaneously occurs. The products of
the reaction are carbon dioxide and water vapor. The balanced chemical equation
is 7H16 + 11O2 → 7CO2 + 8H2O H
= –2877.5 kJ.
Answer:
24805.44 J
Explanation:
Step 1:
Data obtained from the question.
Mass (M) = 464g
Initial temperature (T1) = 120°C
Final temperature (T2) = 219°C
Change in temperature (ΔT) = T2 - T1 = 219°C - 120°C = 99°C
Specific heat capacity of lead (C) = 0.129cal/g°C = 4.184 x 0.129 = 0.54J/g°C
Heat (Q) =?
Step 2:
Determination of the heat Q, required the temperature of lead. This is illustrated below
Q = MCΔT
Q = 464 x 0.54 x 99
Q = 24805.44 J
Therefore, 24805.44 J of heat is required to raise the temperature of lead.
The mass of zinc required to react with HNO3 is 3.45 g
<h3>What is moles of HNO3 reacting?</h3>
The moles of HNO3 reacting is calculated using the formula below:
- moles = concentration × volume
volume = 0.850
volume = 125.0 mL = 0.125 L
Moles of HNO3 = 0.850 × 0.125 = 0.10625 moles
Equation of reaction:
Zn + 2 HNO3 --> Zn(NO3)2 + H2
2 moles of HNO3 reacts with 1 mole of Zn.
moles of zinc reacting = 0.10625/2 = 0.053125
Mass of zinc = moles × molar mass
molar mass of Zn = 65
Mass of zinc = 0.053125 × 65
mass of Zn = 3.45 g
Therefore, the mass of zinc will completely react with 125.0 mL of a solution of nitric acid (HNO3) which has concentration of 0.850M is 3.45 g
Learn more about moles at: brainly.com/question/15356425
He did not apply the fifty newtons of greater force! Ok it says when it needed to have the greater force of fifty the person only put 10N out of the fifty, and left out 40N, that is why it did not work properly.
