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Black_prince [1.1K]
3 years ago
14

Which substance is a reducing agent? A. CO B. F2 C. CO2 D. H2O2 E. FeSO4

Chemistry
2 answers:
IRISSAK [1]3 years ago
6 0

H2O2

\mathtt \red{Hope \:  it  \: helps}

Sergeu [11.5K]3 years ago
3 0
The answer is H202 it’s D
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What is the density of a block of marble that occupies 277 cm3 and has a mass of 928 g? Answer in units of g/cm3 .
Evgesh-ka [11]
V=277cm^{3}\\
m=928g\\\\
d=\frac{m}{V}=\frac{928g}{277cm^{3}}\approx3,35\frac{g}{cm^{3}}
8 0
3 years ago
What is the coefficient of Ca(OH)2 in the equation Ca(OH)2 + HNO3 → Ca(NO3)2 + H2O when balanced using the smallest possible coe
Vikentia [17]

Answer:

The coefficient of Ca(OH)2 is 1

Explanation:

Step 1: unbalanced equation

Ca(OH)2 + HNO3 → Ca(NO3)2 + H2O

Step 2: Balancing the equation

On the right side we have 2x N (in Ca(NO3)2 ) and 1x N on the left side (in HNO3). To balance the amount of N on both sides, we have to multiply HNO3 by 2.

Ca(OH)2 + 2HNO3 → Ca(NO3)2 + H2O

On the left side we have 4x H (2xH in Ca(OH)2 and 2x H in HNO3), on the right side we have 2x H (in H2O). To balance the amount of H on both sides, we have to multiply H2O on the right side, by 2.

Now the equationis balanced.

Ca(OH)2 + 2HNO3 = Ca(NO3)2 + 2H2O

The coefficient of Ca(OH)2 is 1

4 0
3 years ago
Ce cantitate de O se gaseste in 5,8 g hidroxid de magneziu
coldgirl [10]

Answer:

separare pâlnii de picurare balon cotat. 1. 2. 3. 4 5 6 7. 8. 9. 1 ... Mod de lucru: 25 g Na2SO4∙7H2O se dizolvă în cantitatea minim ... Exemple: NaOH – hidroxid de sodiu.

Explanation:

make me as brain liest

4 0
4 years ago
PLEASE HELP DUE TODAY 55 POINTS
Dvinal [7]

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.974 atm

P_2 = final pressure of gas = 0.993 atm

V_1 = initial volume of gas = 27.5 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^oC=273+22.0=295K

T_2 = final temperature of gas = 15.0^oC=273+15.0=288K

Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

Therefore, the final volume of gas will be, 26.3 mL

3 0
3 years ago
Read 2 more answers
What do the following organic chemicals have in common glyphosphate, lindane, 2,4-d, chlordane
otez555 [7]

Glyphosphate, lindane, 2,4-d, chlordane are organic compound that have chlorine in common.

<h3>What is Organic compound?</h3>

Organic compound are group of chemical substance that have carbon and hydrogen atoms in which the bonds are covalently linked together.

Therefore, Glyphosphate, lindane, 2,4-d, chlordane are organic compound that have chlorine in common and these chemicals are use as herbicides that is kill weeds, or to kill insects or pests because of chlorine present in it.

Learn more about organic compounds here.

brainly.com/question/14102593

5 0
2 years ago
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