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Lisa [10]
3 years ago
9

(Thermodynamics)

Chemistry
1 answer:
Degger [83]3 years ago
4 0

Answer:

A) -270 kJ; B) +15 kJ; C) + 70 kJ

Step-by-step explanation:

ΔE = q + w

By convention, anything leaving the system is negative and anything entering the system is positive.

A) ΔE = -220 kJ -  50 kJ = -270 kJ

B) ΔE =  +65 kJ -   50 kJ =   +15 kJ

C) ΔE =  -50 kJ + 120 kJ =  +70 kJ

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\boxed{3}

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\begin{array}{rcl}\dfrac{1}{657 \times 10^{-9}} & = & 1.0974 \times 10^{7}\left ( \dfrac{1}{2^{2}} - \dfrac{1}{n_{f}^{2}} \right )\\\\1.522 \times 10^{6} &= &1.0974\times10^{7}\left(\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \right )\\\\0.1387 & = &\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \\\\-0.1113 & = & -\dfrac{1}{n_{f}^{2}} \\\\n_{f}^{2} & = & \dfrac{1}{0.1113}\\\\n_{f}^{2} & = & 8.98\\n_{f} & = & 2.997 \approx \mathbf{3}\\\end{array}\\\text{The value of $n_{i}$ is }\boxed{\mathbf{3}}

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3 years ago
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