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Lisa [10]
3 years ago
9

(Thermodynamics)

Chemistry
1 answer:
Degger [83]3 years ago
4 0

Answer:

A) -270 kJ; B) +15 kJ; C) + 70 kJ

Step-by-step explanation:

ΔE = q + w

By convention, anything leaving the system is negative and anything entering the system is positive.

A) ΔE = -220 kJ -  50 kJ = -270 kJ

B) ΔE =  +65 kJ -   50 kJ =   +15 kJ

C) ΔE =  -50 kJ + 120 kJ =  +70 kJ

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Explanation:

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               C_{p} = a + bT + cT^{-2}

where, a, b and c are constants.

Their values at 49.0^{o}C are as follows.

     a = 68.62 \times 10^{-3}        

     b = 1.19 \times 10^{-5}

     c = -8.66 \times 10^{10} \times 10^{-8}

Hence, putting the given values into the above formula as follows.

               C_{p} = a + bT + cT^{-2}

    = 68.62 \times 10^{-3} + 1.19 \times 10^{-5} \times 49.0 + -8.66 \times 10^{10} \times 10^{-8} \times (49.0)^{-2} kJ/mol K    

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Thus, we can conclude that the heat capacity of crystalline calcium carbide at 49.0^{o}C is 14.43 kJ/mol K.

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Learn more: brainly.com/question/6284546

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