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Lisa [10]
3 years ago
9

(Thermodynamics)

Chemistry
1 answer:
Degger [83]3 years ago
4 0

Answer:

A) -270 kJ; B) +15 kJ; C) + 70 kJ

Step-by-step explanation:

ΔE = q + w

By convention, anything leaving the system is negative and anything entering the system is positive.

A) ΔE = -220 kJ -  50 kJ = -270 kJ

B) ΔE =  +65 kJ -   50 kJ =   +15 kJ

C) ΔE =  -50 kJ + 120 kJ =  +70 kJ

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Answer: Alpha

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3 years ago
PH CHEM, PLEASE HELP QUICK! NO LINKS/VIRUSES PLEASE!
Contact [7]

Answer:

The pH of the solution is 11.48.

Explanation:

The reaction between NaOH and HCl is:

NaOH  +  HCl  →  H₂O  +  NaCl

From the reaction of 3.60x10⁻³ moles of NaOH and 5.95x10⁻⁴ moles of HCl we have that all the HCl will react and some of NaOH will be leftover:

n_{NaOH}} = n_{i_{NaOH}} - n_{HCl} = 3.60 \cdot 10^{-3} moles - 5.95 \cdot 10^{-4} moles = 3.01 \cdot 10^{-3} moles

Now, we need to find the concentration of the OH⁻ ions.

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Where V is the volume of the solution = 1.00 L                

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Finally, we can calculate the pH of the solution as follows:

pOH = -log([OH^{-}]) = -log(3.01 \cdot 10^{-3}) = 2.52

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3 0
3 years ago
. A container with a volume of 0.50 L contains air at a pressure of 1.0 atm. If the volume is reduced to 0.10 L at constant temp
marin [14]

Answer:

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Explanation:

Data

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Volume 2 = V2 = 0.1 l

Pressure 2 = P2 = x

Formula

To solve this problem use the Boyle's equation

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Solve for P2

                     P2 = V1P1/V2

Substitution

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Simplification

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Result

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3 0
3 years ago
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algol13

Answer:

0.42mole

Explanation:

Given parameters:

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Unknown:

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Solution:

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