Answer:
pH ![= 1.853](https://tex.z-dn.net/?f=%3D%201.853)
Explanation:
For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.
![[H_3O^+] = [HCl] = 0.014](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%20%3D%20%5BHCl%5D%20%3D%200.014)
pH ![= -log [H^+] = -log [H_3O^+]](https://tex.z-dn.net/?f=%3D%20-log%20%5BH%5E%2B%5D%20%3D%20-log%20%5BH_3O%5E%2B%5D)
Substituting the available values in above equation, we can say that the pH of the solution is equal to
![- log (0.014)](https://tex.z-dn.net/?f=-%20log%20%280.014%29)
pH ![= 1.853](https://tex.z-dn.net/?f=%3D%201.853)
pH of a
M HCL solution ![= 1.853](https://tex.z-dn.net/?f=%3D%201.853)
Answer:
Mole of the H2O = 4.5
Number of molecules =4.5 multipled by avogadro's number.
Answer:
The concentration of chloride ion is ![2.82\times10^{-3}\;mol/L](https://tex.z-dn.net/?f=2.82%5Ctimes10%5E%7B-3%7D%5C%3Bmol%2FL)
Explanation:
We know that 1 ppm is equal to 1 mg/L.
So, the
content 100 ppm suggests the presence of 100 mg of
in 1 L of solution.
The molar mass of
is equal to the molar mass of Cl atom as the mass of the excess electron in
is negligible as compared to the mass of Cl atom.
So, the molar mass of
is 35.453 g/mol.
Number of moles = (Mass)/(Molar mass)
Hence, the number of moles (N) of
present in 100 mg (0.100 g) of
is calculated as shown below:
![N=\frac{0.100\;g}{35.453\;g/mol}=2.82\times 10^{-3}\;mol](https://tex.z-dn.net/?f=N%3D%5Cfrac%7B0.100%5C%3Bg%7D%7B35.453%5C%3Bg%2Fmol%7D%3D2.82%5Ctimes%2010%5E%7B-3%7D%5C%3Bmol)
So, there is
of
present in 1 L of solution.
Answer:
1 molecule of oxygen has 2 atoms.
So 2,25 molecules of oxygen have 2 x 2,25 atoms.
2 x 2,25 = 4,5 atoms
There are 4,5 atoms in 2,25 molecules oxygen.