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kondaur [170]
2 years ago
8

Determine the ground-state electron configuration and bond order for each of the Period 2 diatomic molecules. Specify which MO i

s the HOMO and which is the LUMO. List the molecules in order of increasing dissociation and list them in order of bond length. You may need to THINK a bit to get this correct

Chemistry
1 answer:
zloy xaker [14]2 years ago
3 0

Answer:

Explanation:

check the attachment below for correct explanations.

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How would you determine which isotope pair to use for a particular material?
VLD [36.1K]

Answer:

Different types of isotopes are used for different materials or objects. For radiometric dating, uranium-235 is considered best for it while carbon-14 is used for dating of rocks. It is also used for dating of wood samples.

Explanation:

Carbon-14 and uranium-235 are used for different materials or objects for measuring the age of these materials. These two isotopes are radioactive in nature which means they emit gamma radiations which allow us to find the age of different objects. Carbon-14 has a low half life so it can be used for those objects which are present before thousands of years while uranium-235 is used for materials which are millions of years old due to high half life.

7 0
3 years ago
A 0.5 kg ball rolls down a frictionless inclined plane. The height of the inclined plane is 0.5m. What is the kinetic energy of
joja [24]

Answer:

2.45Joules

Explanation:

since kinetic energy is K.E.=1/2mv^{2}

lost in potential energy is gain of kinetic energy

mgh=1/2mv^2

9.8*2*0.5=v^2

v^{2}=9.8

v=\sqrt{9.8} =3.13m/s

now k.e. = 0.5*m*v^{2} =0.5*0.5*9.8 =2.45J

8 0
3 years ago
What is the percent by mass of Hydrogen in C3H6O?
coldgirl [10]

Answer:11.19

Explanation:

And one mole of a hydrogen atom is of 1.008 grams. So, 2 hydrogen moles weighs 2.016 grams. Hence, one mole of water has 2.016 grams of hydrogen mole. Therefore, the percentage composition of hydrogen would be 2.016/18.0152 = 11.19%.

7 0
2 years ago
Read 2 more answers
In a similar analysis, a student determined that the percent of water in the hydrate was 25.3%. the instructor informed the stud
Oxana [17]
Answer is: f<span>ormula for the hydrated compound is CuSO</span>₄·3H₂O.
ω(H₂O) = 25,3% = 0,253.
ω(CuSO₄) = 100% - 25,3%.
ω(CuSO₄) = 74,7% = 0,747.
ω(H₂O) : M(H₂O) = ω(CuSO₄) : M(CuSO₄).
0,253 : M(H₂O) = 0,747 : 159,6 g/mol.
M(H₂O) = (0,253 · 159,6 g/mol) ÷ 0,747.
M(H₂O) = 54 g/mol.
N(H₂O) = 54 g/mol ÷ 18 g/mol.
N(H₂O) = 3.
5 0
3 years ago
Read 2 more answers
Creativity allows scientists to
MA_775_DIABLO [31]
Write more interesting lab reports,draw better diagnosis for reports,look at old problems in new ways and also do more interesting observation to include data
6 0
3 years ago
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