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3 years ago

How do you predict the geometrical shape of NH3 on VSEPR model

Chemistry

1 answer:

Sauron [17]3 years ago

6 0

Answer:

NH3 Ammonia

Explanation:

Ammonia has 4 regions of electron density around the central nitrogen atom (3 bonds and one lone pair). These are arranged in a tetrahedral shape. The resulting molecular shape is trigonal pyramidal with H-N-H angles of 106.7°.

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2. A rock occupies a volume of 20 cm and has a mass of 54 grams. Find the density of this rock.

vredina [299]

The answer is 2.7gm/cm^3 . Density is mass divided by volume .

6 0

3 years ago

A sample of gas has an initial pressure of 1.5 atm, an initial volume of 3.0 L, and an initial temperature of 293K. If the final

Nataliya [291]

Answer:

1.9 L

Explanation:

Step 1: Given data

Initial pressure (P₁): 1.5 atm

Initial volume (V₁): 3.0 L

Initial temperature (T₁): 293 K

Final pressure (P₂): 2.5 atm

Final volume (V₂): ?

Final temperature (T₂): 303 K

Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 1.5 atm × 3.0 L × 303 K / 293 K × 2.5 atm = 1.9 L

6 0

3 years ago

How many moles of MgSiO3 are in 237g of the compound?

Anna35 [415]

For this, we first calculate molecular weight of MgSiO₃:
Atomic masses:
Mg = 24
Si = 28
O = 16

Mr = 24 + 28 + 16 x 3
Mr = 100

moles = mass / Mr
moles = 237 / 100
moles = 2.37

6 0

3 years ago

Hello there :3 Please anwser this Combined gas law problem for me . By the way just anwser #4 for me that’s all . I uploaded the

stellarik [79]

Answer:

136L

Explanation:

p1v1=p2v2

114 x44.0=37.0x V2

V2=136L

6 0

3 years ago

Albus Dumbledore provides his students with a sample of 19.3 g of sodium sulfate. How many oxygen atoms are in this sample

Dimas [21]

Answer:

3.27·10²³ atoms of O

Explanation:

To figure out the amount of oxygen atoms in this sample, we must first evaluate the sample.

The chemical formula for sodium sulfate is Na₂SO₄, and its molar mass is approximately 142.05 $\frac{g}{mol}$ .

We will use stoichiometry to convert from our mass of Na₂SO₄ to moles of Na₂SO₄, and then from moles of Na₂SO₄ to moles of O using the mole ratio; then finally, we will convert from moles of O to atoms of O using Avogadro's constant.

19.3g Na₂SO₄ · $\frac{1 mol Na^2SO^4}{142.05g Na^2SO^4}$ · $\frac{4 mol O}{1 mol Na^2SO^4}$ · $\frac{6.022x10^2^3}{1 mol O}$

After doing the math for this dimensional analysis, you should get a quantity of approximately 3.27·10²³ atoms of O.

3 0

4 years ago