The electric current leaves the battery through the --- complete this blank

Does the shape of molecule affect the chemical bond?

just olya [345]

There is a sharp distinction between ionic and covalent bonds when the geometric arrangements of atoms in compounds are considered. In essence, ionic bonding is nondirectional, whereas covalent bonding is directional.

7 0

3 years ago

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Solve the equation of motion, using Newton's 1 Law F 0, for a general case of M the mass of the wooden block and u, being the co

vodka [1.7K]

Answer:

Explanation:

The first thing to have to make a diagram where we indicate the forces acting on the block, see attached. We have the following

The weight (W) that is vertical

The friction force (fr) that opposes the movement

The driving force (F)

The normal (N) which is the reaction to the support of the body and is perpendicular to the surface

We write a reference system where one axis is parallel to the surface (x axis) and the other is perpendicular to it (Y axis) we decompose the forces on these axes, we see that the only force we have to decompose r is the weight

sin θ = Wx / W ⇒ Wx = W sin θ

cos θ = Xy / W ⇒ Wy = Wcos θ

We write Newton's equations for each axis

N- Wy = 0

F -fr -Wx = m a (1)

The expression for the friction force is

fr = μ N

N = Wy

N = W cos θ

fr = μ mg cosT

We hope, we simplify the acceleration of equation 1

a = F - μ mg cos θ -mg sinθ

a = F - mg (μ cos θ -sin θ)

This is the general equation for movement.

3 0

3 years ago

(5 pt) You tie a cord to a pail of water, and your swing the pail in a vertical circular 0.700 m. What is the minimum speed must

Bas_tet [7]

Answer:

The minimum speed required is 2.62m/s

Explanation:

The value of gravitational acceleration = g = 9.81 m/s^2

Radius of the vertical circle = R = 0.7 m

Given the mass of the pail of water = m

The speed at the highest point of the circle = V

The centripetal force will be needed must be more than the weight of the pail of water in order to not spill water.

Below is the calculation:

$\frac{mV^{2}}{R} = mg$

$V = \sqrt{gR}$

$V = \sqrt{9.81 \times 0.7}$

$V = 2.62 m/s$

6 0

3 years ago

) Force F = − + ( 8.00 N i 6.00 N j ) ( ) acts on a particle with position vector r = + (3.00 m i 4.00 m j ) ( ) . What are (a)

natali 33 [55]

To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.

The vector product between the Force and the radius allows us to obtain the torque, in this way,

$\tau = \vec{F} \times \vec{r}$