GPE=mgh, where m=mass, g=acceleration due to gravity, h=height
We have a force of 675N already, so mg=675N
<span>GPE=mgh=675(26000)=17.55x10^6J</span>
B. An ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.
<h3>When external ear squeeze occurs</h3>
External ear squeeze occurs when gas trapped in the external ear canal remains at atmospheric pressure while the external water pressure increases during descent.
Thus, we can conclude that, an ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.
Learn more about ear squeeze here: brainly.com/question/11430998
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An example would be a pot on a stove. The radiation from the source of the heat (the stove) would make the handle hot by conduction from heat through contact.
Another example could be a metal spoon in a hot cup of coffee. The coffee itself is hot, but since the spoon is in the coffee and making contact, part of the spoon will become hot from the radiation of the source of heat (the hot coffee). Thus, conduction.
Answer:
The required IVP is;
u'' + 196u = 0
where;
u(0) = 0 and
u'(0) = -10
Explanation:
See the attached for explanation
Answer:
330.5 m
Explanation:
In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .
The maximum height will be calculated as;
where ∝ is the angle of launch = 30°
vi= initial launch velocity = 40 m/s
g= 10 m/s²
h= 40²*sin²40° / 2*10
h={1600*0.4132 }/ 20
h= 661.1/2 = 330.5 m
