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Hitman42 [59]
2 years ago
14

Define the following IN YOUR OWN HANDWRITING

Chemistry
1 answer:
k0ka [10]2 years ago
5 0

Answer:

A physical property is a characteristic of matter that is not associated with a change in its chemical composition. Familiar examples of physical properties include density, color, hardness, melting and boiling points, and electrical conductivity.

Explanation:

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How many grams of CaCl2 are in .48 moles?
Ilia_Sergeevich [38]

Answer:

110.984 grams

Explanation:

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A teacher is teaching a lesson on energy transformations. Which explanation is the best at comparing the amount of energy contai
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what is the concentration of an NaOH solution that requires 50 mL of a 1.25 M H2SO4 solution to neutralize 78.0 ml of NaOH​
Dimas [21]

Answer:

  • The answer is the concentration of an NaOH = 1.6 M

Explanation:

The most common way to solve this kind of problem is to use the formula  

  • C₁ * V₁ = C₂ * V₂

In your problem,

For NaOH

C₁ =??     v₁= 78.0 mL = 0.078 L

For H₂SO₄

C₁ =1.25 M     v₁= 50.0 mL = 0.05 L

but you must note that for the reaction of NaOH with H₂SO₄

2 mol of NaOH raect with 1 mol H₂SO₄

So, by applying in above formula

  • C₁ * V₁ = 2 * C₂ * V₂
  • (C₁ * 0.078 L) = (2*  1.25 M * 0.05 L)
  • C₁ = (2*  1.25 M * 0.05 L) / (0.078 L) = 1.6 M  

<u>So, the answer is the concentration of an NaOH = 1.6 M</u>

3 0
3 years ago
What is the percent of S in
ollegr [7]

The percentage of the sulfur (S) in the compound CuSO₄ is 20.1 %.

<h3>What is the mass percentage?</h3>

The percentage of an element in a compound can be determined as the number of parts by mass of that element present in 100 parts by mass of the given compound.

First, calculate the molecular mass of the given compound by the addition of the atomic masses of all the present elements in the molecular formula. Then, the percentage of the elements can be determined by dividing the total mass of the element by the molar mass of the compound multiplied by 100.

Given, the atomic mass of copper, sulfur, and oxygen is 63.55 g, 32.07 g, and 16.0g respectively.

The molecular mass of CuSO₄ =  63.55 + 32.07 + 4(16.0)  = 159.62 g

The mass percentage of the sulphur = (32.07/159.62) × 100 = 20.1 %

Therefore, the mass percentage of the sulfur is equal to 20.1 %.

Learn more about  the mass percentage, here:

brainly.com/question/16750428

#SPJ1

7 0
1 year ago
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