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kap26 [50]
3 years ago
13

Write a quadratic equation with the solutions 3 and 2

Mathematics
1 answer:
jolli1 [7]3 years ago
8 0
We can re-create the quadratic equation by
(x -3) * (x -2)
x^2 -5x + 6 = 0


You might be interested in
Solve for :
OLga [1]

Answer:

d. x = 5

Step-by-step explanation:

Solve for x:

x - 3 = 7 - x

Hint: | Move terms with x to the left hand side.

Add x to both sides:

x + x - 3 = (x - x) + 7

Hint: | Look for the difference of two identical terms.

x - x = 0:

x + x - 3 = 7

Hint: | Add like terms in x + x - 3.

x + x = 2 x:

2 x - 3 = 7

Hint: | Isolate terms with x to the left hand side.

Add 3 to both sides:

2 x + (3 - 3) = 3 + 7

Hint: | Look for the difference of two identical terms.

3 - 3 = 0:

2 x = 7 + 3

Hint: | Evaluate 7 + 3.

7 + 3 = 10:

2 x = 10

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 2 x = 10 by 2:

(2 x)/2 = 10/2

Hint: | Any nonzero number divided by itself is one.

2/2 = 1:

x = 10/2

Hint: | Reduce 10/2 to lowest terms. Start by finding the GCD of 10 and 2.

The gcd of 10 and 2 is 2, so 10/2 = (2×5)/(2×1) = 2/2×5 = 5:

Answer: x = 5

7 0
3 years ago
Lydia is deciding between two different movie streaming sites to subscribe to. Plan A costs $5 per month plus $2.50 per movie wa
Delicious77 [7]
Um Plan B would be two dollars cheaper than plan A ..

I set the equations up like this :

5+2.50x=
24+1.50x=

Only because thats how many movies she plans on watching.

5+2.50(21)=57.50
24+1.50(21)=55.50
7 0
3 years ago
What is the area of a parallelogram if the coordinates of its vertices are (0, -2), (3, 2), (8,2), and (5,-2)?
Llana [10]

Answer:

The area of the parallelogram is 20 units²

Step-by-step explanation:

* Lets explain how to solve the problem

- The vertices of the parallelogram are (0 , -2) , (3 , 2) , (8 , 2) , (5 , -2)

- The side joining the points (0 , -2) and (5 , -2) is a horizontal side

  because the points have same y-coordinates

- The side joining the points (3 , 2) and (8 , 2) is a horizontal side

  because the points have same y-coordinates

∴ These two sides are parallel bases of the parallelogram

∵ The length of any horizontal side = x2 - x1

∴ The length of the side = 5 - 0 = 5 <em>or</em> 8 - 3 = 5

∴ The length of one base of the parallelogram is 5 units

- The height of this base is the vertical distance between these two

  parallel bases

∵ The length of any vertical distance = y2 - y1

∵ y2 = 2 and y1 = -2 ⇒ the y-coordinates of the parallel bases

∴ The length of the vertical distance = 2 - (-2) = 2 + 2 = 4 units

∵ This vertical distance between the two parallel bases is the height

  of these bases

∴ The height of the parallelogram is 4 units

- The area of the parallelogram = base × height

∵ The base = 5 units and the height = 4 units

∴ The area = 5 × 4 = 20 units²

* The area of the parallelogram is 20 units²

7 0
3 years ago
How do i find the unknown side length of #9?
Natali5045456 [20]
You can find the unknown side length by using pythagorean theorem. a²+b²=c²
Simply plug-in numbers into the formula. Your answer is 80.
4 0
3 years ago
A swim meet has 13 contestants signed up for the 100-meter butterfly event. The first heat has 6 swimmers. How many different wa
tino4ka555 [31]

Answer:

6 swimmers in the first heat can be arranged in 1716 different ways.

Step-by-step explanation:

A swim meet has 13 contestants signed up. To calculate the arrangement of first 6 swimmers in first heat we will use combinations because order doesn't matter.

So to select 6 swimmers out of 13 contestants number of different ways

= ^{13}C_{6}

= \frac{13!}{(6!)(13-6)!}

= \frac{13\times 12\times 11\times 10\times 9\times 8\times 7!}{6!\times 7!}

= \frac{13\times 12\times 11\times 10\times 9\times 8}{6\times 5\times 4\times 3\times 2\times 1}

= \frac{1235520}{720}

= 1716

Therefore, 6 swimmers in the first heat can be arranged in 1716 different ways.

5 0
3 years ago
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