Answer:
123added 23
Step-by-step explanation:
Answer:
x = ±i(√6 / 2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
<u>Algebra II</u>
Imaginary root i
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
2x² + 3 = 0
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Subtraction Property of Equality] Subtract 3 on both sides: 2x² = -3
- [Division Property of Equality] Divide 2 on both sides: x² = -3/2
- [Equality Property] Square root both sides: x = ±√(-3/2)
- Simplify: x = ±i(√6 / 2)
We're looking for the two values being subtracted here. One of these values is easy to find:
<span>g(1) = ∫f(t)dt = 0</span><span>
since taking the integral over an interval of length 0 is 0.
The other value we find by taking a Left Riemann Sum, which means that we divide the interval [1,15] into the intervals listed above and find the area of rectangles over those regions:
</span><span>Each integral breaks down like so:
(3-1)*f(1)=4
(6-3)*f(3)=9
(10-6)*f(6)=16
(15-10)*f(10)=10.
So, the sum of all these integrals is 39, which means g(15)=39.
Then, g(15)-g(1)=39-0=39.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
The correct works are:
.
<h3>Function Notation</h3>
The function is given as:
The interpretation when Steven is asked to calculate Blue(s + h) is that:
Steven is asked to find the output of the function Blue, when the input is s + h
So, we have:
Evaluate the exponent
Expand the bracket
So, the correct work is:
<h3>Simplifying Difference Quotient</h3>
In (a), we have:
The difference quotient is represented as:
So, we have:
Evaluate the like terms
Evaluate the quotient
Hence, the correct work is:
Read more about function notations at:
brainly.com/question/13136492
Answer:
230 - 151 + 180 + (43 - 12) = 290
Step-by-step explanation:
Use PEMDAS.
Evaluate the expression in the parentheses:
230 - 151 + 180 + (43 - 12)
43 - 12 = 31
230 - 151 + 180 + 31
Add and Subtract From Left to Right:
230 - 151 + 180 + 31
79 + 180 + 31
259 + 31
290
<em>None of the given options are correct. </em>
