Question

A 16 Kb (=16,384 bit) memory array is designed as a square with an aspect ratio of one (number of rows is equal to the number of columns). The minimum number of address lines needed for the row decoder is________.

Answer 1

Answer:

7

Explanation:

The structure of memory chip is given by multiplying the number of rows and column ie M X N

he number of address line required for row decoder is n where M =$2^{n}$ or expressed in logarithmic form we have

$n= log_2 M$

In this case M=N since number of rows is equal to the number of columns

Therefore, $M X N= M x M= M^{2}=16 kb=16384 b= 2^{4} \times 2^{10}= 2^{14}$

$M^{2}= 2^{14}$

Therefore,

M=128

Since $n=log_2 M$

$n=log_2 128=7$

Therefore, address lines should be at least 7