Given:
size of scale model = 4(size of pump)
power ratio of pump and scale model = 5:1
Solution:
Let the diameter of scale model and pump be 
and 
respectively
and head be 
and 
respectively
Now, power, P is given as a function of head(H) and dischagre(Q)
P = 
(1)
From eqn (1):
and
So,
Therefore,
= 
=
= 
= 
= 
Answer:
See explaination
Explanation:
The volume flow rate Q Q QQ of a fluid is defined to be the volume of fluid that is passing through a given cross sectional area per unit time.
Kindly check attachment for the step by step solution of the given problem.
Answer:
1. The magnetic flux line form a closed loop.
2. The magnetic flux line repel each other.
3. The magnetic flux line never intersect.
Answer:
The electrical work for the process is 256.54 Btu.
Explanation:
From the ideal gas equation:
n = PV/RT
n is the number of moles of air in the tank
P is initial pressure of air = 50 lbf/in^2 = 50 lbf/in^2 × 4.4482 N/1 lbf × (1 in/0.0254m)^2 = 344736.2 N/m^2
V is volume of the tank = 40 ft^3 = 40 ft^3 × (1 m/3.2808 ft)^3 = 1.133 m^3
T is initial temperature of air = 120 °F = (120-32)/1.8 + 273 = 321.9 K
R is gas constant = 8.314 J/mol.k
n = 344736.2×1.133/8.314×321.9 = 145.94 mol
The thermodynamic process is an isothermal process because the temperature is kept constant.
W = nRTln(P1/P2) = 145.94×8.314×321.9×ln(50/25) = 145.94×8.314×321.9×0.693 = 270669 J = 270669 J × 1 Btu/1055.06 J = 256.54 Btu
Answer: Incoherent question
Explanation: This is an act of plagiarism at subjecting the tutor to unnecessary stress at answering the purported question.
