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rosijanka [135]
3 years ago
11

Round 8.795 to the nearest cent

Mathematics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

8.80

Step-by-step explanation:

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You buy a lottery ticket to a lottery that costs $10 per ticket. There are only 100 tickets available to be sold in this lottery
riadik2000 [5.3K]

Answer:

Loss of $1.20

Step-by-step explanation:

The possible outcomes for this lottery and their probabilities are:

- a 1 in 100 chance of winning $450

- a 2 in 100 chance of winning $120

- a 4 in 100 chance of winning $30

- a 93 in 100 chance of losing $10

Therefore, the expected value of this lottery when buying one ticket is:

E(X) = \frac{1}{100}*\$450+ \frac{2}{100}*\$120+ \frac{4}{100}*\$30-\frac{93}{100}*\$10 \\E(X) = -\$1.2

Therefore, you are expected to lose $1.2 per ticket.

3 0
3 years ago
What is the value of x
mezya [45]

Answer:

x=9.5

Step-by-step explanation:

In order to find the answer, we know that 6x + 4x - 5 = 90

Next we want to combine like terms: 10x - 5 = 90.

Now we have to add 5 to 90 in order to get x on its own.  10x = 95

Now solve for x by dividing 95 by 10: x=9.5

4 0
2 years ago
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Find the area. Will mark brainliest
chubhunter [2.5K]

Answer:

80.64

Step-by-step explanation:

12.6*6.4=80.64

4 0
3 years ago
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True or false? it is possible for a system of linear equations to have exactly two solutions.
maksim [4K]

Answer: False

Systems of linear equations can only have 0, 1, or an infinite number of solutions. These two lines cannot intersect twice. The correct answer is that the system has one solution.

Step-by-step explanation:

4 0
3 years ago
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Solve screen shot attachment EASY
Leona [35]

Answer:

x = \frac{-3d-9}{k-d}

Step-by-step explanation:

Step 1: Write out equation

d(-3 + x) = kx + 9

Step 2: Distribute <em>d</em>

-3d + dx = kx + 9

Step 3: Subtract 9 on both sides

-3d + dx - 9 = kx

Step 4: Subtract dx on both sides

-3d - 9 = kx - dx

Step 5: Factor out <em>x</em>

-3d - 9 = x(k - d)

Step 6: Divide both sides by k - d

x = \frac{-3d-9}{k-d}

8 0
3 years ago
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