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3 years ago

How many grams of hydrogen gas would be needed to form 8.0 grams of water? H2+O2=H2O

Chemistry

1 answer:

damaskus [11]3 years ago

7 0

8 H2= 0.90 g , hope that helps
you with your work

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Help me please would be happy if you did

Natasha_Volkova [10]

You have to read the passage and compare and contrast the story

8 0

3 years ago

The compound consists of 40% carbon and 6.71% hydrogen. Its mass of 1 liter of steam is 2.4 g. What is the formula of the compou

AveGali [126]

I think it is CH2O.

If i'm wrong srry

7 0

2 years ago

Pls help ——————————<br> —————-

Marina86 [1]

Answer:

X has 9 Electrons, 9 Protons and 10 Neutrons

X is Fluorine

Explanation:

19 in X is Nucleon number

So, if you minus 19 by 9 down there (which is proton number) you'll get 10 (Neutron number).

Now, Proton = Electron. That's why Electron is 9 too. I figured that X is Fluorine bcuz it has 9 Electrons. If you venture around in the periodic table, fluorine is the ninth element innit.

hope this helps ya ＼(^o^)／

7 0

2 years ago

The length breadth and thickness of a brick is 18cm 8 cm and 5cm respictively find the area of the widest part of rhe brick

Sunny_sXe [5.5K]

Answer:

144cm²

Explanation:

Given dimensions:

Length x breadth x thickness

18cm x 8cm x 5cm

The widest part of this figure will be the face containing the length and the breadth.

The breadth is the width of the figure;

Area of the widest part = length x breadth = 18cm x 8cm = 144cm

The area of the widest part of the figure is 144cm²

4 0

3 years ago

What would be the freezing point of a solution that has a molality of 1.324 m which was prepared by dissolving biphenyl (C12H10)

lbvjy [14]

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.

$\Delta T = i \times Kf \times m = 1 \times 6.90 \°C/m \times 1.324m = 9.14 \°C$

where,

i: van 't Hoff factor (1 for non-electrolytes)
Kf: cryoscopic constant
m: molality

The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:

$T = 80.26 \° C - 9.14 \° C = 71.12 \° C$

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

Learn more: brainly.com/question/2292439

3 0

2 years ago