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mihalych1998 [28]
4 years ago
6

The decay of a radioactive isotope can be theoretically modeled with the following equation, where C0 is the initial amount of t

he element at time zero and k is the decay rate of the isotope. Create a proper plot of the decay of isotope A [k = 1.48 hours]. Allow time to vary on the abscissa from 0 to 5 hours with an initial concentration of 10 grams of isotope A.

Engineering
1 answer:
liubo4ka [24]4 years ago
6 0

That problem could answered easyly in Matlab,

We know that c=c_0e^{\frac{t}{k}}

So whit this program we can make it,

<em />

<em>figure('color','white')</em>

<em>initial=10;</em>

<em>decay_rate=1.48</em>

<em>time=[0:0:1:5];</em>

<em>concen=initial*exp(-time/decay_rate);</em>

<em>plot(time,concen)</em>

<em>grid</em>

<em>title('Decay of the Isotope A')</em>

<em>xlabel('Time (hours'))</em>

<em>ylabel('concentration in grams')</em>

<em />

<em />

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A large plate is fabricated from a steel alloy that has a plane strain fracture toughness of 78 MPa (70.98 ksi). If the plate is
Reika [66]

Answer:

minimum length of a surface crack is 15.043 mm

Explanation:

given data

strain fracture toughness K = 78 MPa

tensile stress = 345 MPa

Y = 1.04

to find out

minimum length of a surface crack

solution

we find here length of critical interior flaw from formula that is

α  =  \frac{1}{\pi} (\frac{K}{\sigma Y})^2     ....................1

put here value we get

α  =  \frac{1}{\pi} (\frac{78*\sqrt{10^3} }{345*1.04})^2

α  = 15.043 mm

so minimum length of a surface crack is 15.043 mm

7 0
3 years ago
Write a statement that calls the recursive method backwardsAlphabet() with parameter startingLetter.
Tcecarenko [31]

Recursion refers to the act of calling a function itself. With the use of this strategy, complex problems can be reduced to more manageable, simpler ones. Recursion might be a little challenging to comprehend. The best method to figure out how it works is to experiment with it.

<h3>How to write a programme by recursive method ?</h3>

The process of making a function call itself is known as recursion. With the use of this strategy, complex problems can be reduced to more manageable, simpler ones. Recursion might be a little challenging to comprehend. Experimenting with it is the most effective way to learn how it functions.

public class Recursive Calls {

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System.out.println(currLetter);

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backwards Alphabet(--currLetter);

}

return;

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char starting Letter = '-';

starting Letter = 'z';

// Your solution goes here

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To learn more about recursive method refer to :

brainly.com/question/24167967

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6 0
2 years ago
A 14 inch diameter pipe is decreased in diameter by 2 inches through a contraction. The pressure entering the contraction is 28
Delicious77 [7]

Answer:

5984.67N

Explanation:

A 14 inch diameter pipe is decreased in diameter by 2 inches through a contraction. The pressure entering the contraction is 28 psi and a pressure drop of 2 psi occurs through the contraction if the upstream velocity is 4.0 ft/sec. What is the magnitude of the resultant force (lbs) needed to hold the pipe in place?

from continuity equation

v1A1=v2A2

equation of continuity

v1=4ft /s=1.21m/s

d1=14 inch=.35m

d2=14-2=0.304m

A1=pi*d^2/4

0.096m^2

a2=0.0706m^2

from continuity once again

1.21*0.096=v2(0.07)

v2=1.65

force on the pipe

(p1A1- p2A2) + m(v2 – v1)

from bernoulli

p1 + ρv1^2/2 = p2 + ρv2^2/2

difference in pressure or pressure drop

p1-p2=2psi

13.789N/m^2=rho(1.65^2-1.21^2)/2

rho=21.91kg/m^3

since the pipe is cylindrical

pressure is egh

13.789=21.91*9.81*h

length of the pipe is

0.064m

AH=volume of the pipe(area *h)

the mass =rho*A*H

0.064*0.07*21.91

m=0.098kg

(193053*0.096- 179263.6* 0.07) + 0.098(1.65 – 1.21)

force =5984.67N

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4 years ago
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Answer:

Change in entropy S = 0.061

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3 years ago
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Answer:

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