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mihalych1998 [28]
3 years ago
6

The decay of a radioactive isotope can be theoretically modeled with the following equation, where C0 is the initial amount of t

he element at time zero and k is the decay rate of the isotope. Create a proper plot of the decay of isotope A [k = 1.48 hours]. Allow time to vary on the abscissa from 0 to 5 hours with an initial concentration of 10 grams of isotope A.

Engineering
1 answer:
liubo4ka [24]3 years ago
6 0

That problem could answered easyly in Matlab,

We know that c=c_0e^{\frac{t}{k}}

So whit this program we can make it,

<em />

<em>figure('color','white')</em>

<em>initial=10;</em>

<em>decay_rate=1.48</em>

<em>time=[0:0:1:5];</em>

<em>concen=initial*exp(-time/decay_rate);</em>

<em>plot(time,concen)</em>

<em>grid</em>

<em>title('Decay of the Isotope A')</em>

<em>xlabel('Time (hours'))</em>

<em>ylabel('concentration in grams')</em>

<em />

<em />

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Write the output expression for a NOR gate with inputs , , and .​
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Answer:

Logic NOR Gate Equivalent

The Boolean expression for a logic NOR gate is denoted by a plus sign, ( + ) with a line or Overline, ( ‾‾ ) over the expression to signify the NOT or logical negation of the NOR gate giving us the Boolean expression of: A+B = Q.

4 0
2 years ago
Turning a screw with a screwdriver pushes the screw into the wood. The force is __________ over many turns
IrinaK [193]

Answer:

repeated?

Explanation:

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5 0
2 years ago
The current entering the positive terminal of a device is i(t)= 6e^-2t mA and the voltage across the device is v(t)= 10di/dtV.
liberstina [14]

Answer:

a) 2,945 mC

b) P(t) = -720*e^(-4t) uW

c) -180 uJ

Explanation:

Given:

                           i (t) = 6*e^(-2*t)

                           v (t) = 10*di / dt

Find:

( a) Find the charge delivered to the device between t=0 and t=2 s.

( b) Calculate the power absorbed.

( c) Determine the energy absorbed in 3 s.

Solution:

-  The amount of charge Q delivered can be determined by:                      

                                       dQ = i(t) . dt

                  Q = \int\limits^2_0 {i(t)} \, dt = \int\limits^2_0 {6*e^(-2t)} \, dt = 6*\int\limits^2_0 {e^(-2t)} \, dt

- Integrate and evaluate the on the interval:

                   = 6 * (-0.5)*e^-2t = - 3*( 1 / e^4 - 1) = 2.945 C

- The power can be calculated by using v(t) and i(t) as follows:

                 v(t) = 10* di / dt = 10*d(6*e^(-2*t)) /dt

                 v(t) = 10*(-12*e^(-2*t)) = -120*e^-2*t mV

                 P(t) = v(t)*i(t) = (-120*e^-2*t) * 6*e^(-2*t)

                 P(t) = -720*e^(-4t) uW

- The amount of energy W absorbed can be evaluated using P(t) as follows:

                 W = \int\limits^3_0 {P(t)} \, dt = \int\limits^2_0 {-720*e^(-4t)} \, dt = -720*\int\limits^2_0 {e^(-4t)} \, dt

- Integrate and evaluate the on the interval:

                  W = -180*e^-4t = - 180*( 1 / e^12 - 1) = -180uJ

6 0
3 years ago
An Otto cycle engine is analyzed using the cold air standard method. Given the conditions at state 1, compression ratio (r), and
lilavasa [31]

Answer:

Explanation:

The detailed and careful step by step calculation and analysis is as shown with appropriate formula in the attached files

4 0
2 years ago
Pls follow me in brainly​
Sergio [31]

Answer:

sure

Add on:

!!

5 0
3 years ago
Read 2 more answers
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