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mihalych1998 [28]
3 years ago
6

The decay of a radioactive isotope can be theoretically modeled with the following equation, where C0 is the initial amount of t

he element at time zero and k is the decay rate of the isotope. Create a proper plot of the decay of isotope A [k = 1.48 hours]. Allow time to vary on the abscissa from 0 to 5 hours with an initial concentration of 10 grams of isotope A.

Engineering
1 answer:
liubo4ka [24]3 years ago
6 0

That problem could answered easyly in Matlab,

We know that c=c_0e^{\frac{t}{k}}

So whit this program we can make it,

<em />

<em>figure('color','white')</em>

<em>initial=10;</em>

<em>decay_rate=1.48</em>

<em>time=[0:0:1:5];</em>

<em>concen=initial*exp(-time/decay_rate);</em>

<em>plot(time,concen)</em>

<em>grid</em>

<em>title('Decay of the Isotope A')</em>

<em>xlabel('Time (hours'))</em>

<em>ylabel('concentration in grams')</em>

<em />

<em />

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Answer: r = 0.8081; s = -0.07071

Explanation:

A = (150i + 270j) mm

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R = rA + sB + C = 0i + 0j

R = r(150i + 270j) + s(300i - 450j) + (-100i - 250j) = 0i + 0j

R = (150r + 300s - 100)i + (270r - 450s - 250)j = 0i + 0j

Equating the i and j components;

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solving simultaneously,

r = 0.8081 and s = -0.07071

QED!

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