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mihalych1998 [28]
3 years ago
6

The decay of a radioactive isotope can be theoretically modeled with the following equation, where C0 is the initial amount of t

he element at time zero and k is the decay rate of the isotope. Create a proper plot of the decay of isotope A [k = 1.48 hours]. Allow time to vary on the abscissa from 0 to 5 hours with an initial concentration of 10 grams of isotope A.

Engineering
1 answer:
liubo4ka [24]3 years ago
6 0

That problem could answered easyly in Matlab,

We know that c=c_0e^{\frac{t}{k}}

So whit this program we can make it,

<em />

<em>figure('color','white')</em>

<em>initial=10;</em>

<em>decay_rate=1.48</em>

<em>time=[0:0:1:5];</em>

<em>concen=initial*exp(-time/decay_rate);</em>

<em>plot(time,concen)</em>

<em>grid</em>

<em>title('Decay of the Isotope A')</em>

<em>xlabel('Time (hours'))</em>

<em>ylabel('concentration in grams')</em>

<em />

<em />

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Complete Question

The complete question is shown on the first uploaded image

Answer:

a) The required additional minterms  for f so that f has eight primary implicants with two literals and no other prime implicant are m_{2},m_{3},m_{7},m_{8},m_{11},m_{12},m_{13},m_{14} and m_{15}

b) The essential prime implicant are c' d',a'b',ab and cd

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The explanation is shown on the second third and fourth image

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3 years ago
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3 years ago
The in-situ dry density of a sand is 1.72Mg/m3. The maximum and minimum drydensities, determined by standard laboratory tests, a
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Answer:

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Explanation:

The following information was provided by this question

Pd = 1.72mg/mg³

Pd max = 1.81 mg/mg³

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We substitute into the formula. This formula is contained in the attachment.

[(1/1.54)-(1/1.72)]/[1/1.54 - 1/1.81]

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Answer:

See attachment for detailed answer.

Explanation:

Download pdf
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