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3 years ago

Explain with examples: What are the reasons of a successful and unsuccessful software project?

Engineering

1 answer:

malfutka [58]3 years ago

3 0

Answer: Not Enough Time

Often, the deadline date is decided before the project starts and is non-negotiable. This deadline results in a headlong rush to get started on the assumption, the sooner you begin coding, the sooner you'll finish.

A rush to start coding is almost always the wrong approach. It is important to spend the time to create a good design. Not having a good design leads to continuing changes throughout the development phase. When this happens, time and budget are consumed at a rapid rate.

Solution: Make time to create a good design. Don't be tempted to jump straight in and begin coding. Assign time to this task and the rest of the project will run much better. It will improve your reputation when you deliver something that fulfils the customers' expectations and works the first time correctly.

Explanation:

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Which word from the passage best explains what the web in the passage symbolizes

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Answer:

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Explanation:

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3 years ago

It describes the physical and social elements common to this work. Note that common contexts are listed toward the top, and less

QveST [7]

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3 years ago

Read 2 more answers

Air at 38°C and 97% relative humidity is to be cooled to 14°C and fed into a plant area at a rate of 510m3/min. (a) Calculate th

Katarina [22]

To develop the problem it is necessary to apply the concepts related to the ideal gas law, mass flow rate and total enthalpy.

The gas ideal law is given as,

$PV=mRT$

Where,

P = Pressure

V = Volume

m = mass

R = Gas Constant

T = Temperature

Our data are given by

$T_1 = 38\°C$

$T_2 = 14\°C$

$\eta = 97\%$

$\dot{v} = 510m^3/kg$

Note that the pressure to 38°C is 0.06626 bar

PART A) Using the ideal gas equation to calculate the mass flow,

$PV = mRT$

$\dot{m} = \frac{PV}{RT}$

$\dot{m} = \frac{0.6626*10^{5}*510}{287*311}$

$\dot{m} = 37.85kg/min$

Therfore the mass flow rate at which water condenses, then

$\eta = \frac{\dot{m_v}}{\dot{m}}$

Re-arrange to find $\dot{m_v}$

$\dot{m_v} = \eta*\dot{m}$

$\dot{m_v} = 0.97*37.85$

$\dot{m_v} = 36.72 kg/min$

PART B) Enthalpy is given by definition as,

$H= H_a +H_v$

Where,

$H_a$ = Enthalpy of dry air

$H_v$ = Enthalpy of water vapor

Replacing with our values we have that

$H=m*0.0291(38-25)+2500m_v$

$H = 37.85*0.0291(38-25)-2500*36.72$

$H = 91814.318kJ/min$

In the conversion system 1 ton is equal to 210kJ / min

$H = 91814.318kJ/min(\frac{1ton}{210kJ/min})$

$H = 437.2tons$

The cooling requeriment in tons of cooling is 437.2.

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3 years ago

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kupik [55]

Answer: the correct answer is D

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2 years ago

Discuss the applications of numerical weather forecasting

olchik [2.2K]

Numerical weather prediction (NWP) uses mathematical models of the atmosphere and oceans to predict the weather based on current weather conditions. Though first attempted in the 1920s, it was not until the advent of computer simulation in the 1950s that numerical weather predictions produced realistic results. A number of global and regional forecast models are run in different countries worldwide, using current weather observations relayed from radiosondes, weather satellites and other observing systems as inputs.

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3 years ago