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Tasya [4]
2 years ago
5

A steel rectangular tube has outside dimensions of 150 mm x 50 mm and a wall thickness of 4 mm. State the inside dimensions, the

area of its cross section, and the weight of a piece 1.22 m long.
Engineering
1 answer:
lara [203]2 years ago
6 0

Answer:

 inside dimension  = 142 mm \times 42 mm

cross section area = 7.5\times 10^{-3} m^2

mass of 1.2 meter log steel  = 1.843\times 10^{-3} \rho

Explanation:

given data:

Outside dimension of steel rectangular = 150 mm\times 50mm

Thickness = 4 mm

Long = 1.22 m

inside dimension will be = (150- 8)mm \times ( 50-8)mm

                                         = 142 mm \times 42 mm

cross section area = 150\times 50 mm^2

                               = 7500\times 10^{-6} m^2

                               = 7.5\times 10^{-3} m^2

let the density be assumed as \rho

mass of 1.2 meter log steel will be = 1.2  \times (7.5\times 10^{-3} -  0.142\times 0.048)\times \rho

                                                       = 1.843\times 10^{-3} \rho

                                                       

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Create a project named CarDealer that contains a Form for an automobile dealer. Include options for at least three car models. A
PIT_PIT [208]

Answer:

/****************** The code for a form application that uses radioButtons * *and displays new form based on the user selection *****************/

Using system;

Using system windows forms;

namespace CarDealer

{

Public partial class Form1 : Form

{

public Form1()

{

//default constructor to initialize components

InitializeComponent();

}

//when user clicks on the details button

private void detail_Click

(Object sender, EventArgs e)

{

if (model1,Checked)

{

Forms2 f = new Form2()

f.ShowDialog()

model1.Checked = false

}

if (model2.Checked)

{

Form3 f = new Form3();

f.ShowDialog();

model2.Checked = false;

}

if (model3.Checked)

{

Form4 f = new Form4();

f.ShowDialog();

model3.Checked = false;

}

}

}

}

Explanation:

Program plan

- Design form: Place label controls with text as select car model and one empty label control to display total price. Change front type and size from each other labels properties window.

- Add three radio buttons with text Renault Kwit, Tata Tiago, Mahindra KUV 100.

- Add button with text View Details.

- Add 3 new windows form from project menu for each car model.

- Change form name and respective car models.

- Place picturebox control to each form by using image property add .jpeg image and place label control containing price of each model to each form

- When user select car model and click on view details, new form containing car model details is displayed.

Form Design is attached below

7 0
2 years ago
ABS system is necessary?
Monica [59]

Explanation:

I think it helps you

I don't know the answer sorry

3 0
2 years ago
A centrifugal pump is required to pump water to an open water link situated 4 km away from the location of the pump through a pi
11111nata11111 [884]

Answer:

P= 5.5 bar

Explanation:

Given that

L= 4000 m

d= 0.2 m

Friction factor(F) = 0.01

speed V= 2 m/s

Head = 5 m

Head loss due to friction

h_f=\dfrac{FLV^2}{2gd}

h_f=\dfrac{0.01\times 4000\times 2^2}{2\times 9.81\times 0.2}

h_f=40.77m

So the total head(H) = 5 + 40.77 + 10.3 =56.07

Where 10.3 m is the atmospheric head.

We know that

P=ρ g H

So total Pressure

P= 1000 x 9.81 x 56.07 Pa

P=5.5\times 10^5\ Pa

P= 5.5 bar

5 0
3 years ago
Which of the following allows team members to visualize a design model from a variety of perspectives?
julsineya [31]

Answer: from what i know im pretty sure its isometrics or sketches im certain its sketches but not 100%

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8 0
3 years ago
Read 2 more answers
The Cv factor for a valve is 48. Compute the head loss when 30 GPM of water passes through the valve.
dlinn [17]

Answer:

The head loss in Psi is 0.390625 psi.

Explanation:

Fluid looses energy in the form of head loss. Fluid looses energy in the form of head loss when passes through the valve as well.

Given:

Factor cv is 48.

Flow rate of water is 30 GPM.

GPM means gallon per minute.

Calculation:

Step1

Expression for head loss for the water is given as follows:

c_{v}=\frac{Q}{\sqrt{h}}

Here, cv is valve coefficient, Q is flow rate in GPM and h is head loss is psi.

Step2

Substitute 48 for cv and 30 for Q in above equation as follows:

48=\frac{30}{\sqrt{h}}

{\sqrt{h}}=0.625

h = 0.390625 psi.

Thus, the head loss in Psi is 0.390625 psi.

 

5 0
2 years ago
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