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Tasya [4]
2 years ago
5

A steel rectangular tube has outside dimensions of 150 mm x 50 mm and a wall thickness of 4 mm. State the inside dimensions, the

area of its cross section, and the weight of a piece 1.22 m long.
Engineering
1 answer:
lara [203]2 years ago
6 0

Answer:

 inside dimension  = 142 mm \times 42 mm

cross section area = 7.5\times 10^{-3} m^2

mass of 1.2 meter log steel  = 1.843\times 10^{-3} \rho

Explanation:

given data:

Outside dimension of steel rectangular = 150 mm\times 50mm

Thickness = 4 mm

Long = 1.22 m

inside dimension will be = (150- 8)mm \times ( 50-8)mm

                                         = 142 mm \times 42 mm

cross section area = 150\times 50 mm^2

                               = 7500\times 10^{-6} m^2

                               = 7.5\times 10^{-3} m^2

let the density be assumed as \rho

mass of 1.2 meter log steel will be = 1.2  \times (7.5\times 10^{-3} -  0.142\times 0.048)\times \rho

                                                       = 1.843\times 10^{-3} \rho

                                                       

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