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Tasya [4]
3 years ago
5

A steel rectangular tube has outside dimensions of 150 mm x 50 mm and a wall thickness of 4 mm. State the inside dimensions, the

area of its cross section, and the weight of a piece 1.22 m long.
Engineering
1 answer:
lara [203]3 years ago
6 0

Answer:

 inside dimension  = 142 mm \times 42 mm

cross section area = 7.5\times 10^{-3} m^2

mass of 1.2 meter log steel  = 1.843\times 10^{-3} \rho

Explanation:

given data:

Outside dimension of steel rectangular = 150 mm\times 50mm

Thickness = 4 mm

Long = 1.22 m

inside dimension will be = (150- 8)mm \times ( 50-8)mm

                                         = 142 mm \times 42 mm

cross section area = 150\times 50 mm^2

                               = 7500\times 10^{-6} m^2

                               = 7.5\times 10^{-3} m^2

let the density be assumed as \rho

mass of 1.2 meter log steel will be = 1.2  \times (7.5\times 10^{-3} -  0.142\times 0.048)\times \rho

                                                       = 1.843\times 10^{-3} \rho

                                                       

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melamori03 [73]

Answer:

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Explanation:

5 0
3 years ago
Read 2 more answers
Discuss 7 habits of highly effective people and how important are ethics in today's society​
kompoz [17]

Answer:

Explanation:

The 7 Habits of Highly Effective People, is a book written and first published in 1989. It is a business and self-help book that was written by Stephen Covey. The seven habits include

Being proactive

Starting anything with the end in mind

First things first

Always thinking towards a win-win situation

Seeking initially to understand, then going on to want to be understood

Synergize, and lastly

Growing

7 0
3 years ago
Knowing that v = –8 m/s when t = 0 and v = 8 m/s when t = 2 s, determine the constant k. (Round the final answer to the nearest
docker41 [41]

Answer:

a)We know that acceleration a=dv/dt

So dv/dt=kt^2

dv=kt^2dt

Integrating we get

v(t)=kt^3/3+C

Puttin t=0

-8=C

Putting t=2

8=8k/3-8

k=48/8

k=6

5 0
3 years ago
Which type of engineering design uses an already existing design
Snezhnost [94]

Answer:

Reverse engineering

Explanation:

Reverse Engineering is the remaking of already made products following the deconstruction and examination of the product to make known the product design, code and architecture features, gain knowledge of the composition and construction in a scientific research approach

Reverse engineering is also known as back engineering and consists of three main stages

1) Recovery implementation

2) Design recovery

3) Recovery analysis.

3 0
3 years ago
Substance Specific Heat (cal/g°C) Specific Heat (J/g°C) water 1.00 4.18 steam 0.96 4.02 alcohol 0.59 2.47 ice 0.50 2.09 wood 0.4
Jobisdone [24]

Answer:

C) 43,2°C

Explanation:

<em>Sensible heat</em> is the amount of thermal energy that is required to change the temperature of an object, the equation for calculating the heat change is  given by:

Q=msΔT

where:

  • Q, heat that has been absorbed or realeased by the substance [J]
  • m, mass of the substance [g]
  • s, specific heat capacity [J/g°C]
  • ΔT, changes in the substance temperature [°C]

To solve the problem, we clear ΔT of the equation and then replace our data:

Q=890 [J],

m=16,6 [g],

s=2,74 [J/g°C]

Q=msΔT.......................ΔT=Q/ms

ΔT=\frac{890 J}{16,6g*2,47\frac{J}{gC}}=21,7°C

As:

ΔT=Tfinal-Tinitial

Tfinal=ΔT+Tinitial

Tfinal=21,7+21,5=43,2°C

The final temperature of the ethanol is 43,2°C.

4 0
4 years ago
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