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pantera1 [17]
3 years ago
11

Argon is compressed in a polytropic process with n=1.2 from 120 kPa and 10 °C to 800 kPa in a piston cylinder device. Determine:

(a) The work produced and, (b) Heat transferred during this compression process, in KJ/kg.
Engineering
1 answer:
Jlenok [28]3 years ago
5 0

Answer:

a. W = - 108.89 kJ/kg

b. q =  - 75.846 kJ/kg

Given:

n = 1.2

Pressure, P = 120 kPa

Temperature, T = 10^{\circ} = 283 K

Pressure, P' = 800 kPa

Solution:

(a) Work Produced:

Now, using the relation:

W = \frac{RT}{1 - n}[(\frac{P'}{P})^(1 - \frac{1}{n}) - 1]

where

R = Rydberg's constant

Now,

W = \frac{283\times0.208}{1 - 1.2}[(\frac{800}{120})^(1 - \frac{1}{1.2}) - 1]

W = \frac{283\times0.208}{- 0.2}[(6.67)^(0.16) - 1] = - 108.89 kJ/kg

Now,

\frac{T'}{T}= (\frac{P'}{P})^{1 - \frac{1}{n}}

T'= T(\frac{800}{120})^{1 - \frac{1}{1.2}}

T'= 1.37\times 283 = 388.48 K

(b) Heat tranferred, q = C_{v}(T' - T) + W

q = 0.3122(388.84 - 283) - 108.89 = - 75.846 kJ/kg

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Answer:

Ma=\frac{260}{330} \\Ma=0.7878

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Explanation:

Mach Number:

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