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MA_775_DIABLO [31]
3 years ago
11

How much 6.0M HNO(small 3) is needed to neutralize 39mL of 2 M KOH

Chemistry
1 answer:
Digiron [165]3 years ago
8 0
Equation of reaction 
<span>KOH+HNO3--->KNO3+H2O </span>
<span>CA=6.0M, CB=2.0M, VA=?, VB=39ml, na=1, nb=1 </span>
<span>CAVA/CBVB=na/nb </span>
<span>6*VA/2*39=1/1 </span>
<span>6VA/78=1 </span>
<span>6VA=78 </span>
<span>VA=78/6. VA=13ml. </span>
<span>VA=13ml.</span><span>
Hope this helped!!!!! </span>Don't forget Brainliest!!!!! You can always PM me if you don't want to waste any points!!!!!
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