Answer:

The air in the atmosphere consists of nitrogen, oxygen, which is the life-sustaining substance for animals and humans, carbon dioxide, water vapour and small amounts of other elements (argon, neon, etc.). Higher in the atmosphere air also contains ozone, helium and hydrogen.
Hello can we study chemistry?
Answer:
V₂ = 1223.2 mL
Explanation:
Given data:
Pressure of gas = 820.4 mmHg
Initial volume of gas = 900.0 mL
Initial temperature = 25.0°C (25+273=298K)
Final temperature = 132.0°C (132.0 +273 = 405 K)
Final volume = ?
Solution:
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 900.0 mL × 405 K / 298 k
V₂ = 364500 mL.K / 298 K
V₂ = 1223.2 mL
V1 = 5L = 5000ml V2 = ?
T1 = 25°C = 25+273 T2 = -120°C
= 297K = -120+273
= 153K
By Charles Law,
V1/T1 = V2/T2
5000/297 = V2/153
By solving,
V2 = 2.576L
According to Bronsted-Lowry theory of acids and bases, an acid is proton donor and a base is proton acceptor. When an acid loses the proton, it forms the conjugate base of the acid. Similarly when a base accepts a proton, it forms the conjugate acid if that base. A conjugate acid base pair differs by a single proton.
Given the weak acid
. It can lose a proton to form the conjugate base.

Therefore, the conjugate base of
is
.