Answer:- 0.143 M
Solution:- HCl and NaOH reacts in 1:1 mol ratio as shown in the below reaction:
Let's calculate the initial moles of HCl and the moles of NaOH added to it:
= 0.075 mol HCl
= 0.025 mol NaOH
Since they react in 1:1 mol ratio, 0.025 mol of NaOH will react with 0.025 moles of HCl.
Remaining moles of HCl = 0.075 - 0.025 = 0.050
Total volume of the resulting solution = 0.250 L + 0.100 L = 0.350 L
So, the concentration of HCl in the resulting solution =
= 0.143 M
Hence, the concentration of HCl acid in the resulting solution is 0.143 M.
Hi there! The simplest whole-number ratio of the atoms in a molecule of formula is called the Empirical formula.
All the answers in the equation above will be Zero (0)
Explanation:
As it is known that molecule is a non-linear molecule. Therefore, its isochoric heat capacity will be as follows.
=
= 18 R
Also,
where, = molar heat capacity
M = molecular mass
= specific heat
Hence, calculate the value of as follows.
This means that value of isochoric specific heat is .
Yes, we have to assume ideal gas behavior because for ideal gas:
dU =
Whereas for real gases "" has to be added here.
Explanation:
The molarity of a solution is defined like the number of moles of solute per liters of solution.
molarity = moles of solute/(volume of solution in L)
We know the volume of solution in L.
volume of solution = 0.65 L
To go from the mass of our solute in grams to moles we have to use its molar mass.
mass of NaCl = 63 g
molar mass of NaCl = 58.44 g/mol
moles of NaCl = 63 g * 1 mol/(58.44 g)
moles of NaCl = 1.078 moles
Finally we can find the molarity of the solution
molarity = moles of NaCl/(volume of solution)
molarity = 1.078 moles/(0.65 L)
molarity = 1.66 M
Answer: the molarity of the solution is 1.66 M.