Answer:
No frills = $0.25(x)
simple = $6 + $0.05(x)
set equal to each other
0.025(x) = 6 + 0.05(x)
rearrange like terms together
0.025(x) - 0.05(x) = 6
0.020(x) = 6
x =300
Simple plan will be cheaper once you use more than 300 checks
Step-by-step explanation:
Subtract the 2nd row from the 1st row
5x = 5
Solve for x in the equation above
x = 1
Substitute x = 1 into any of the two equations above
Let's pick the first equation; 4x + 3y = -5
4 * 1 + 3y = -5
Solve for y in the equation above
y = -3
Therefore,
<u>x = 1</u>
<u>y = -3</u>
Four batches can be made with 6 cups
Ok. So, if 8 pens cost £12. Then we would divide £12 by 8. Each pen costs £1.5.
So now we are going to multiply £1.5 and 10. £1.5*10=15.
The total of 10 pens is £15.
I hope this helps, if you need any additional help, just ask. I am here to help you as needed.
Answer:
Option C
Step-by-step explanation:
You forgot to attach the expression that models the cost of the camping trip during the three days. However, by analyzing the units, the answer can be reached.
The total cost has to be in units of $.
There are two types of costs in the problem:
Those that depend on the number of days ($/day
)
Those that depend on the number of students and the number of days ($/(student * day))
If there are 3 days of camping and b students, then you have to multiply the costs that depend on the days by the number of days (3), and the costs that depend on the number of students you have to multiply them by 'b'
So, if the costs that must be multiplied by 'b' are only those that depend on the number of students, the coefficient of b must be:
3 days (Cost of training + Cost of food Miscellaneous expenses :).
Therefore the correct answer is option C:
C. It is the total cost of 3 days per student of Mr. Brown, with training, food and miscellaneous expenses.
The expression that represents the total expense should have a formula similar to this:
![y = (3 days) *([\frac{20.dollars}{(day * student)} + \frac{30.dollars}{(student * day)} + \frac{50.dollars}{(student * day)}] b + \frac{200}{day}) + 1050.dollars](https://tex.z-dn.net/?f=y%20%3D%20%283%20days%29%20%2A%28%5B%5Cfrac%7B20.dollars%7D%7B%28day%20%2A%20student%29%7D%20%2B%20%5Cfrac%7B30.dollars%7D%7B%28student%20%2A%20day%29%7D%20%2B%20%5Cfrac%7B50.dollars%7D%7B%28student%20%2A%20day%29%7D%5D%20b%20%2B%20%5Cfrac%7B200%7D%7Bday%7D%29%20%2B%201050.dollars)
y = 3 ($ 100b + $ 200) + $ 1050