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olya-2409 [2.1K]

2 years ago

15

6. A 2000 kg spacecraft is located 9.2x10 m from the center of the earth. The mass of the earth

1 answer:

Zina [86]2 years ago

3 0

The answer is -i, trust me.

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The H line in Calcium is normally at 396.9nm. however, in a star’s spectrum it is measured at 398,1 nm. How fast is the star mov

konstantin123 [22]

H line of Calcium spectrum is normally given as 396.9 nm

Now from a distant star we measured it as 398.1 nm

So here this change in the wavelength of distant star is due to Doppler's effect of light as per which when source of light moves towards the observer then the frequency of light received will appear different from its actual frequency

So here we can say as per Doppler's effect of light

$\frac{\Delta \nu}{\nu_0} = \frac{v}{c}$

$\frac{\nu' - \nu}{\nu_0} = \frac{v}{c}$

$\frac{\frac{1}{\lambda} - \frac{1}{\lambda'}}{\frac{1}{\lambda}} = \frac{v}{c}$

$\frac{\lambda' - \lambda}{\lambda'} = \frac{v}{c}$

given that

$\lambda' = 398.1 nm$

$\lambda = 396.9 nm$

$c = 3 * 10^8 m/s$

$\frac{398.1 - 396.9}{398.1} = \frac{v}{3*10^8}$

$v = 3*10^8 * \frac{1.2}{398.1}$

$v = 9.04 * 10^5 m/s$

so the start is moving away with speed 9.04 * 10^5 m/s because when wavelength is more than the real wavelength then its frequency is less which mean it is moving away from the Earth

5 0

3 years ago

Is kane brown a true country singer?<br> A.yes<br> B.no

Kryger [21]

Answer: hes not a country singer if thats what your asking

Explanation:

6 0

3 years ago

Read 2 more answers

What would Hubble's constant be if we found one galaxy moving away at 30,000 km/s at a distance of 600 Mpc?

lora16 [44]

Answer:

H₀ = 1.6 x 10⁻¹⁸ s⁻¹

Explanation:

The Hubble's Constant can be found by the following formula:

$v = H_o D\\\\H_o = \frac{v}{D}$

where,

H₀ = Hubble's Constant = ?

v = speed of galaxy = 30000 km/s = 3 x 10⁷ m/s

D = Distacance = 600 Mpc = (6 x 10⁸ pc)(3.086 x 10¹⁶ m/1 pc)

D = 18.52 x 10²⁴ m

Therefore,

$H_o = \frac{3\ x\ 10^7\ m/s}{18.52\ x\ 10^{24}\ m}$

<u>H₀ = 1.6 x 10⁻¹⁸ s⁻¹</u>

3 0

2 years ago

The diameter of Earth (to two significant figures) is 7900 miles. Calculate its circumference.

Bess [88]

Answer:

The circumference of the Earth is 24818.58 miles

Explanation:

Analysis conceptual : The formula of the circumference is the following:

L= π*D Formula (1)

Where:

L : is the length of the circumference in miles (mi)

π : is the constant

D : is the diameter of the circumference in miles (mi)

Known data

π = 3.1416

D= 7900 miles: Diameter of the Earth

Problem development

We apply the formula 1 to calculate the circumference of the Earth (L):

L= π*7900 miles

L= 24818.58 miles

8 0

3 years ago

Along the line connecting the two charges, at what distance from the charge q1 is the total electric field from the two charges

Nostrana [21]

Answer:

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

Explanation:

Here two charges are placed at distance "d" apart

now the net value of electric field at some position between two charges will be ZERO

so we will have

electric field due to charge 1 = electric field due to charge 2

$E_1 = E_2$

Let the position where net field is zero will lie at distance "r" from q1

$\frac{kq_1}{r^2} = \frac{kq_2}{(d-r)^2}$

now we will have

$\frac{(d - r)^2}{r^2} = \frac{q_2}{q_1}$

now square root both sides

$\frac{d}{r} - 1 = \sqrt{\frac{q_2}{q_1}}$

now we have

$\frac{d}{r} = \sqrt{\frac{q_2}{q_1}} + 1$

so we have

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

8 0

3 years ago