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3 years ago

Why is it important to know the location of active and inactive faults in our country?

Physics

1 answer:

Andrew [12]3 years ago

5 0

Answer:

I hope this helps.

Explanation:

It's important to know the location of an active fault in order to determine the magnitude of the expected earthquake. There is a chance than an inactive fault can become active again. It's important that we take the locations into account in order to be prepared and ready for if it occurs.

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What is the relation between centre of gravity and stability

maw [93]

Explanation:

tilting it will raise the height of its center of gravity.

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3 years ago

An experiment is performed to test the effect of three different types of water on the growth of a plant. The test is done by us

natima [27]

I think the correct answer would be D. The tap water in the experiment is one the three test conditions of the independent variable, the type of water. The independent variable in a experiment is the one being manipulated or the one being changed. In this case, it is the type of water.

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3 years ago

Read 2 more answers

A light bulb whose resistance is 240 ohms is connected to a 120 voltage source. What is the current through the bulb?

Sedaia [141]

Answer:

0.5A

Explanation:

Using $R = \frac{V}{I}$ ,

R is the resistance (in Ohms)

V is the voltage (in V)

I is the current (in A)

$240=\frac{120}{I}$

I = 0.5A

7 0

2 years ago

A roller coaster car may be approximated by a block of mass m. Thecar, which starts from rest, is released at a height h above t

elena55 [62]

Answer:

The first part can be solved via conservation of energy.

$mgh = mg2R + K\\K = mg(h-2R)$

For the second part,

the free body diagram of the car should be as follows:

- weight in the downwards direction

- normal force of the track to the car in the downwards direction

The total force should be equal to the centripetal force by Newton's Second Law.

$F = ma = \frac{mv^2}{R}\\mg + N = \frac{mv^2}{R}$

where $N = 0$ because we are looking for the case where the car loses contact.

$mg = \frac{mv^2}{R}\\v^2 = gR\\v = \sqrt{gR}$

Now we know the minimum velocity that the car should have. Using the energy conservation found in the first part, we can calculate the minimum height.

$mgh = mg2R + \frac{1}{2}mv^2\\mgh = mg2R + \frac{1}{2}m(gR)\\gh = g2R + \frac{1}{2}gR\\h = 2R + \frac{R}{2}\\h = \frac{5R}{2}$

Explanation:

The point that might confuse you in this question is the direction of the normal force at the top of the loop.

We usually use the normal force opposite to the weight. However, normal force is the force that the road exerts on us. Imagine that the car goes through the loop very very fast. Its tires will feel a great amount of normal force, if its velocity is quite high. By the same logic, if its velocity is too low, it might not feel a normal force at all, which means losing contact with the track.

7 0

3 years ago

an electromagnetic wave propagates in a vacuum in the x-direction. In what direction does the electric field oscilate

sweet [91]

Answer:

<em>The electric field can either oscillates in the z-direction, or the y-direction, but must oscillate in a direction perpendicular to the direction of propagation, and the direction of oscillation of the magnetic field.</em>

Explanation:

Electromagnetic waves are waves that have an oscillating magnetic and electric field, that oscillates perpendicularly to one another. Electromagnetic waves are propagated in a direction perpendicular to both the electric and the magnetic field. If the wave is propagated in the x-direction, then the electric field can either oscillate in the y-direction, or the z-direction but must oscillate perpendicularly to both the the direction of oscillation of the magnetic field, and the direction of propagation of the wave.

5 0

3 years ago