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umka21 [38]
3 years ago
9

NEED HELP NOW DUE TODAY Which of these statements is most likely correct about Newton's law on gravity? (2 points)

Physics
1 answer:
yKpoI14uk [10]3 years ago
4 0
_______________________a
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According to the law of conservation of mass, what is the mass of water
DENIUS [597]

Answer:

<em>according to the conservation of mass,</em>

<em>according to the conservation of mass,the mass of the water is 36.04g</em><em>r</em><em>a</em><em>m</em><em>s</em><em> </em>

Explanation:

Hope It Help you

3 0
3 years ago
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4.
Pie

Answer:

b

Explanation:

it compresses hot air turning into cool air almost like a reverse tornado

3 0
3 years ago
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When a pendulum is at the center position, what is true of the kinetic and potential energy?
guajiro [1.7K]

Answer:

Kinetic energy

Explanation:

When a pendulum is swinging about its mean position, the total energy is conserved.

At the mean position, the kinetic energy is maximum but the potential energy is zero.

At the extreme position, the potential energy is maximum but the kinetic energy is zero.

5 0
3 years ago
Consider a series RLC circuit where R = 855 Ω and C = 6.25 μF. However, the inductance L of the inductor is unknown. To find its
sashaice [31]

Answer:

L= 0.059 mH

Explanation:

Given that

R = 855 Ω and C = 6.25 μF

V= 84 V

Frequency

ω = 51900 1/s

We know that

\omega=\sqrt{\dfrac{1}{LC}}

L=Inductance

C=Capacitance

ω =angular Frequency

ω² L C =1

(51900)² x L x 6.25 x 10⁻⁶ = 1

L= 5.99 x 10⁻⁵ H

L= 0.059 mH

6 0
3 years ago
A point source at the origin emits sound of frequency 175 Hz uniformly in all directions. On the x-axis at x=100 m, the sound in
hammer [34]

Answer:

Multiple answers:

1. Power output P=17.59W

2.Intensity 160m I=17.6W/m^{2}

3. dB = 77.3

4. f=178.5 Hz

Explanation:

First one comes from the expression

I=\frac{P}{4\pi r^{2} }

where<em> I </em>is the intensity, <em>P </em>is the power and <em>r </em>is the radio of the spherical wave, or in this case, the distance <em>x</em>. I solved for the Power by multiplying Intensity with the area (4\pi x^{2}

Second one is done with:

\frac{I_{2} }{I_{1} } =\frac{x^{2}_{1} }{x^{2} _{2}}

Solving for Intensity 2, the result mentioned.

The third is simply computed with

dB=10*log\frac{I}{10^{-12} }

And finally the last one is done with doppler effect, taking into account the speed of the air as in 10ºC 337m/s.

f=f_{initial} *(\frac{s+v_{receiver} }{s+v_{source} } )

Where <em>Finitial</em> is the frequency emitted and <em>s</em> is the speed of the sound. The wind blowing in positive is, in principle, going away of the observer.

8 0
3 years ago
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