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fomenos
2 years ago
12

What is the molecular formula of a compound that has a molecular mass of 54 and the empirical formula is C2H3

Chemistry
1 answer:
iren [92.7K]2 years ago
8 0
To find the molecular formula from the empirical formula, you need to find a multiple (x) that will give you the molar mass of the compound which in the question is 54 g/mol.

If C₂H₃ is the empirical formula
 molar mass of empirical formula = (12 × 2) + (1 × 3) g/mol
                                                     =  27 g/mol
let x = multiple
let molecular formula = C₂ₓ H₃ₓ

            multiple = molecular mass ÷ empirical mass
                         =  54 g/mol ÷  27 g/mol
                         =  2


If molecular formula = C₂ₓ H₃ₓ

then molecular formula = C₂₍₂₎H₃₍₂₎

                                      = <span>C₄H</span>₆

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a 6.7 volume of air, initially at 23 degrees celsius and .98 atm, is compressed to 2.7 L while heated to 125 degrees celsius. Wh
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Learn more about ppm:brainly.com/question/16727593

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1 year ago
The density of mercury is 13.6 g/mL what is the density in lbs/L ( 1 lb hint =0.454 kg )
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Answer:

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Explanation:

Hello,

In this case, since 454 g are equivalent to 1 pound and 1000 millilitres are equivalent to 1 liter, the required density is computed below by applying the corresponding conversion factor:

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Regards.

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3 years ago
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