Data:
V1 = 6.7 liter
T1 = 23° = 23 + 273.15 K = 300.15 K
P1 = 0.98 atm
V2 = 2.7 liter
T2 = 125° = 125 + 273.15 K = 398.15 K
P2 = ?
Formula:
Combined law of ideal gases: P1 V1 / T1 = P2 V2 / T2
=> P2 = P1 V1 T2 / (T1 V2)
P2 = 0.98 atm * 6.7 liter * 398.15 K / (300.15K * 2.7 liter)
P2 = 3.22 atm
sand silt and clay but also has large amounts of Carbonate. NOT carbonite.
The amount of the magnesium in the sample in ppm is 497 ppm.
<h3>What is parts per million?</h3>
The term parts per million refers to one of the manners in which concentration is expressed. It is common in oceanography and analytical chemistry.
Given that;
Mass of Mg= 0.0549 g
Mass of the sample = 110.52 g
Amount in PPM = 0.0549 g/110.52 g * 10^6
= 497 ppm
Learn more about ppm:brainly.com/question/16727593
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Answer:

Explanation:
Hello,
In this case, since 454 g are equivalent to 1 pound and 1000 millilitres are equivalent to 1 liter, the required density is computed below by applying the corresponding conversion factor:

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