Remember that in this case pressure is equal to 1.00 atm and temperature is equal to 273.15K. So,
P
V
=
n
R
T
→
n
=
P
V
R
T
=
1.00
a
t
m
⋅
7.0
L
0.082
a
t
m
⋅
L
m
o
l
⋅
K
⋅
273.15
K
=
0.31
Since we know hydrogen's molar mass (
2.0
g
m
o
l
), we can determine the mass
m
H
2
=
n
⋅
m
o
l
a
r
.
m
a
s
s
=
0.31
m
o
l
e
s
⋅
2.0
g
m
o
l
=
0.62
g
If indeed you are dealing with STP, remember that, under these conditions, 1 mole of any ideal gas occupies
22.4
L
. So,
n
=
V
V
m
o
l
a
r
=
7.0
L
22.4
L
=
0.31
moles
And, once again,
m
=
0.31
⋅
2.0
=
0.6
Transport of Na+ from a place of low concentration to a place of higher concentration. <u>This is the right answer.</u>
<u />
The sodium-potassium pump is the most common and well-known example of active transport. At the cell membrane, the sodium-potassium pump moves 3 sodium ions out of the cell and two potassium ions into the cell per ATP. Examples of active transport include the uptake of glucose in the human intestine and the uptake of minerals and ions into the root hair cells of plants.
One of the greatest examples of active transport is the movement of calcium ions out of cardiomyocytes. Cells secrete proteins such as enzymes, antibodies, and various other peptide hormones. Amino acids are transported across the intestinal mucosa of the human intestine. The movement of ions or molecules across cell membranes to regions of a higher concentration is assisted by enzymes and requires energy.
Learn more about Active transport here:-brainly.com/question/25802833
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Answer:
The reason is because Charle's Law which states that volume is directly proportional to temperature. So, for the temperature to be absolute zero, there would need to be no volume. It's Impossible.
Explanation:
Answer:
-776 KJ/mol
Explanation:
We must look towards the balanced reaction equation in order to obtain the number of electrons transferred in the redox reaction.
3Cu(s) + 2MnO4^-(aq) + 8H^+(aq)------>3Cu2+(aq) + 2MnO2(s) + 4H2O(l)
We can easily see that copper lost six electrons while Manganese gained six electrons hence n=6
ΔG =-nFEcell
Where;
n= 6
F = 96500 C
Ecell=+1.34
ΔG = -(6 * 96500 * 1.34)
ΔG = -776 KJ/mol
Answer:
The answer to your question is: 43 %
Explanation:
Data
NO = 7 mol
O2 = 5 mol
NO2 = 3 mol
percent yield = ?
Reaction
2NO(g) + O2(g) ⇒ 2NO2(g)
Proportion of reactants
From the reaction 2 moles of NO / 1 moles of O2 = 2
From the experiment 7 moles of NO / 5 moles of O2 = 1.4
Then, the limiting reactant is NO.
Rule of three
2 moles of NO -------------- 2 moles of NO2
7 moles of NO -------------- x
x = (7 x 2) / 2
x = 7 moles of NO2
% yield = experimental/ theoretical x 100
% yield = 3/7 x 100
% yield = 42.9 ≈ 43
