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Free_Kalibri [48]
3 years ago
10

The height of a street light is 21 feet. It casts a 20−foot shadow. At the same time, a man standing next to the street light ca

sts a 5−foot shadow. How tall is the man? If needed, round the answer to the nearest hundredth.

Mathematics
2 answers:
ivolga24 [154]3 years ago
6 0
5.25 ft

just divide 20/5 and that equal 4. so to find the height of the man you divide 21 by 4
stealth61 [152]3 years ago
3 0

Answer:

The answer to your question is The man is 5.25 ft height

Step-by-step explanation:

Data

Height street light = 21 ft

Shadow street light = 20 ft

Shadow man = 5 ft

height man = ?

Process

1.- Use the Thales' theorem to solve this problem

               \frac{21}{20} = \frac{h}{5}

2.- Solve for h

              h = \frac{5(21)}{20}

3.- Simplify

              h = \frac{105}{20}

4.- Result

              h = 5.25 ft

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32

Step-by-step explanation:

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3 years ago
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Helpppppp please !!?
ch4aika [34]
Please refer to my image where it shows my work as I’m explaining.

Okay, for system 1:

1. I am using the elimination method to solve. So I check if all the terms are lined up and if any are the same. I found that 2X are common in both equations.

2. The goal is to “eliminate” the term hence the name. So I can choose to add or subtract. I chose subtraction because 2 - 2 equals 0 which is our goal. Solve for the rest of the terms. This will lead to getting y =4. Refer to image for the work.

3. Last step to to find the X value. We do this by picking any of the given equations,then substitute y with 4 and solve to eventually get x = 10. Refer to image for the work.

FOR SYSTEM 2:

1. Again, I am using the elimination method to solve. I noticed that NONE of the terms are in common so I will have to intervene. You can chose any term to create a match with but I chose Y since it was the one I could use the smallest number to multiply with. When multiplying, DONT just multiply Y, multiply ALL the terms in the equation or else everything will crash.

2. Now that I have terms in common I can choose to add or subtract. I chose subtraction because 2-2 equals zero which is what we want. Solve look at image for my process which lead to X = -8

3. Last step is to find the value of Y. Chose any of the given equations in system 2 then substitute x with -8. Refer to image to see process. It lead to y = 20


To check the validity of the answers, substitute the x and y values into both equations both side of the equal side should have the same number. Hope that helped!

6 0
3 years ago
Find the distance between the points (1,3) and (5,0).
Irina18 [472]

distance between two points is [(x2-x1)^2 +(y2-y1)^2]^1/2

I.e,[{5-1)^2+(0-3)^2]^1/2

[16+9]^1/2

[25]^1/2

5

5 0
3 years ago
PLEASE ANSWER THIS ASAP, I WILL BE GIVING YOU A THANKS! .
timama [110]

Answer:

D.) 12

Step-by-step explanation:

16x - 3(4x + 5) = 2x + 9

16x - 12x - 15 = 2x + 9

4x - 2x = 15 + 9

2x = 24

2x/2 = 24/2

x = 12

Check:

16x - 3(4x + 5) = 2x + 9

16(12) - 3(4(12) + 5) = 2(12) + 9

192 - 3(48 + 5) = 2(12) + 9

192 - 3(53) = 24 + 9

192 - 159 = 33

33 = 33

3 0
2 years ago
You decide to enter in a rowing competition. To train, you go to the boat house and begin rolling down stream. You row for the s
fredd [130]

Answer:

Time spent rowing down stream =100\ seconds

Speed of boat in still water =14\ ms^{-1}

Step-by-step explanation:

Let speed of boat in still water be = x\ ms^{-1}

Speed of current = 10\ ms^{-1}

Speed of boat down stream = \textrm{Speed of boat in still water +Speed of current}= (x+10)\ ms^{-1}

Distance rowed down stream = 2400 m

Time spent rowing down stream = \frac{Distance}{Speed}=\frac{2400}{x+10}\ s = \frac{Distance}{Speed}=\frac{2400}{x+10}\ s

Speed of boat up stream = \textrm{Speed of boat in still water -Speed of current}= (x-10)\ ms^{-1}

Distance rowed up stream = \frac{1}{6} \textrm{ of distance rowed downstream}=\frac{1}{6}\times 2400 = 400\ m

Time spent rowing up stream = \frac{Distance}{Speed}=\frac{400}{x-10}\ s

We know that,

\textrm{Time spent rowing down stream =Time spent rowing up stream}

So,

\frac{2400}{x+10}=\frac{400}{x-10}

Cross multiplying

2400(x-10)=400(x+10)

Dividing both sides by 400

\frac{2400(x-10)}{400}=\frac{400(x+10)}{400}

6(x-10)=x+10

6x-60=x+10

Adding 60 to both sides.

6x-60+60=x+10+60

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Subtracting both sides by x

6x-x=x+70-x

5x=70

Dividing both sides by 5.

\frac{5x}{5}=\frac{70}{5}

∴ x=14

Speed of boat in still water =14\ ms^-1

Time spent rowing down stream =\frac{2400}{14+10}=\frac{2400}{24}=100\ s

3 0
3 years ago
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