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3 years ago

Carlos is 6 feet tall.

Mathematics

2 answers:

Paul [167]3 years ago

4 0

Answer; Carlos would be 72 inches tall

Step-by-step explanation:

because 1 foot = 12 inches . and he is 6 feet tall so 12 x 6 = 72 !

Lynna [10]3 years ago

3 0

Hey there!

All we need to do is multiply 6 by 12

6 * 12 = 72

Therefore, Carlos is 72 inches tall

Hope this helps you!

God bless ❤️

xXxGolferGirlxXx

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Is x = 6 a solution to the equation 5(x – 3) = x + 13?

deff fn [24]

Answer:

x=6 is not a solution

Step-by-step explanation:

We can substitute 6 as x to find out:

5(6-3)=6+13

first, because of PEMDAS we'll do 6-3

5(3)=6+13

multiply 5 by 3 and add 6 and 13

15=19

Since the statement is not true, that means that x=6 is not a solution

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2 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

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sashaice [31]

Answer:

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Step-by-step explanation:

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aev [14]

9514 1404 393

Answer:

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Step-by-step explanation:

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x + 4y = -5

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