First bring the 9 to the other side by subtracting it so you get the equation; x^2+10x-9=0 and you answer would be x=9 and x=1. you may have wrote the question own wrong? is the x^2 negative? if so i give my answer :)
Standard form is x + y = number.
y = -2/5 x
y + 2/5 x = 0
2/5 x + y = 0
In standard form, the coefficient of x or y cannot be a fraction.
Therefore we have to multiply the whole equation by 5.
2x + 5y = 0
Completing the squares tells us exactly what square root we will need to calculate our answer.
Using the formula below you can find these answers:
![A(x-h)^2 + K = 0 (x-5)^ 2 = - K/A ](https://tex.z-dn.net/?f=A%28x-h%29%5E2%20%2B%20K%20%3D%200%0A%28x-5%29%5E%202%20%3D%20-%20K%2FA%0A)
Does this make sense?