While in a car at 4.47 meters per second a passenger drops a ball from a height of 0.70 meters above the top of a bucket how far
in front of the bucket should the passenger drop the ball such that the ball will land in the bucket?
1 answer:
Answer:
1.7 m
Explanation:
= Velocity of ball in x direction = 4.47 m/s
= Velocity of ball in y direction = 0
g = Acceleration due to gravity = 
t = Time taken
= Vertical displacement = 0.7 m

Horizontal displacement is given by

The passenger should throw the ball 1.7 m in front of the bucket.
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