When the Moon orbits Earth, what is the centripetal force?
1 answer:
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Answer:
10. True. vA = - ¼ vB , pA = - pB
Explanation:
Let us propose the solution of this problem, as the cars are released let us use the conservation of the moment.
Initial before releasing the cars
p₀ = 0
Final after releasing cars
= mA vA + mB vB
p₀ =
0 = mA vA + mB vB
vA = - mB / mA vB
They indicate that mA = 4 mB
vA = - ¼ vB
Let's write the amount of movement for each body
pA = mA vA = 4 mB (- ¼ vB
pA = -mB vB
pB = mB vB
pA = - pB
Let's check the answers
1 False
2 False
3 False
4 false
5 False
6 False
7 False
8 False
9 False
10. True. The speed and amount of movement values are correct
Answer:
(a) ΔP=0.0245 kPa
(b) P=9.14 kPa
(c)ΔP=0.0245 kPa
Explanation:
(a) As it is perfect gas we can use
(P₁V₁)/T₁=(P₂V₂)/T₂
Since this constant volume so
P₁/T₁=P₂/T₂
T₂ is change in temperature
T₂=1.00+273.16
T₂=274.16 K
ΔP=6.71449-6.69
ΔP=0.0245 kPa
(b) As
(c) Same steps as in part (a)
ΔP=9.164-9.14
ΔP=0.0245kPa