A bullet of mass 20 gram traveling hoirzentally at 100 m/s embeds itself in the center of a block of wood mass 1 kg which is sus
pended by light vertical string 1 meter in length get cleared to maximum inclination of the string to the vertical?
1 answer:
Answer:
36.5°
Explanation:
Momentum is conserved immediately before and after the collision.
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂
(0.020 kg) (100 m/s) + (1 kg) (0 m/s) = (0.020 kg) v + (1 kg) v
v = 1.96 m/s
After the collision, energy is conserved.
KE = PE
½ m v² = mgh
½ v² = gh
h = v² / (2g)
h = (1.96 m/s)² / (2 × 9.8 m/s²)
h = 0.196 m
We need the angle that the string forms with the vertical. Knowing the length of the string and the height that the block rises, we can do some geometry (see attached diagram).
L − L cos θ = h
L (1 − cos θ) = h
1 − cos θ = h / L
cos θ = 1 − h / L
cos θ = 1 − (0.196 m / 1 m)
θ = 36.5°
Round as needed.
You might be interested in
Answer:
he same direction the magnitude of the resultant is equal to the scalar sum of the magnitude of the forces, but if they are applied in different directions the magnitude must be found using the Pythagorean theorem
Explanation:
When there are several applied forces, if they are all in the same direction the magnitude of the resultant is equal to the scalar sum of the magnitude of the forces, but if they are applied in different directions the magnitude must be found using the Pythagorean theorem, so which the resulting dowry is less than the sum of the magnitudes.
Let's carry out an example with two forces, F1 and F2 of equal magnitudes
if they are in the same direction
F_total = F₁ + F₂ = 2 F
if they are at 90º
F_total =
if they are at 180º
F_total = F₁ -F₂ = 0