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Naddik [55]
4 years ago
11

If the Mass Number is the sum of the protons and neutrons in an atom, what is the mass number of

Physics
1 answer:
gogolik [260]4 years ago
4 0

Answer:

It's 31

Explanation:

add 15 and 16

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What does the vibrating object do to the air particles around it ?
dimulka [17.4K]

Answer:

When an object vibrates, it causes the molecules in the air around it to move. These molecules collide with nearby molecules, forcing them to vibrate as well. As a result, they collide with more surrounding air molecules.

Explanation:

3 0
3 years ago
How long would it take me to travel 48 milllion miles at 200000 mph?
MakcuM [25]
For this question, you must divide 48 million by two hundred thousand to get your answer. The quotient of these number is 240, which if reduced to days, is exactly ten days.
5 0
3 years ago
6. Your 60-watt light bulb is plugged into a 110-volt household outlet and left on for 3 hours. The utility company charges you
elena55 [62]

Answer:

0.0198 dollars

Explanation:

We first obtain the total energy drawn by the light bulb in kilowatt-hour (kW-hr) using the following relationship;

Energy = power rating x time

Given;

power rating = 60W,

time = 3hrs

Therefore,

Energy consumed = 60W x 3hr

Energy consumed = 180W-hr = 0.18kW-hr

We then multiply this energy in kW-hr by he amount charged per unit kW-hr as follows;

Given that 1kW-hr= 0.11 dollars

0.18kW-hr = 0.18 x 0.11

                = 0.0198 dollars

6 0
3 years ago
Read 2 more answers
An electric motor operates a pump that irri-
PolarNik [594]

Answer:

a. 5A

b. 39.60%

Explanation:

The computation is shown below:

a. The current does it draw is

= v ÷ R

= 110v  ÷ 22

= 5A

b. Now the efficiency of the motor is

n = mgh ÷ vlt

= (10,000 × 9.8 × 8) ÷ (5 × 3600 × 110)

= 784000 J ÷ 1,980,000

= 39.60%

hence, the above formulas are applied & the same is relevant

7 0
3 years ago
A planet has two small satellites in circular orbits around the planet. The first satellite has a period 18.0 hours and an orbit
sasho [114]

Answer:

Time period of second satellite will be 50.904 hour

Explanation:

We have given time period of first satellite T_1=18hour

Orbital radius of first satellite a_1=2\times 10^7m

Orbital radius of second satellite a_2=4\times 10^7m

We have to find the time period of second satellite.

Time period of satellite is equal to T=2\pi \sqrt{\frac{a^3}{G(M_1+M_2)}}

From the relation we can see that T\propto a^{\frac{3}{2}}

\frac{T_1}{T_2}=\frac{a_1^\frac{3}{2}}{a_2^\frac{3}{2}}

\frac{18}{T_2}=\frac{(2\times 10^7)^\frac{3}{2}}{(4\times 10^7)^\frac{3}{2}}

\frac{18}{T_2}=(\frac{1}{2})^\frac{3}{2}

T_2=50.904hour

Time period of second satellite will be 50.904 hour

4 0
3 years ago
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