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3 years ago

Some children are underfed and often have no place to sleep. According to

Physics

1 answer:

jeka943 years ago

3 0

Answer:

Physiological needs

Explanation:

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A point on a wheel of radius 40 cm that is rotating at a constant 5.0 revolutions per second is located 0.20 m from the axis of

Margarita [4]

Answer:

$197.2 m/s^2$

Explanation:

The centripetal acceleration of a point moving by circular motion is given by:

$a=\omega^2 r$

where

$\omega$ is the angular velocity

r is the distance from the axis of rotation

The point on the wheel makes 5.0 revolutions per second, so the frequency is

$f=\frac{5}{1}=5 Hz$

and the angular velocity is

$\omega=2\pi f = 2\pi (5)=31.4 rad/s$

While the distance of the point from the axis of rotation is

$r=0.20 m$

Substituting, we find the acceleration:

$a=(31.4)^2(0.20)=197.2 m/s^2$

5 0

3 years ago

Read 2 more answers

A train car with mass m1 = 515 kg is moving to the right with a speed of v1 = 7.5 m/s and collides with a second train car. The

Anna [14]

Answer:

For the first situation, we first need to find the mass of the second train car.

In order to do that, we apply the conservation of the amount of movement:

$515*7.5+m2*0=(m1+m2)*4.8$

and we have as a result:

m2 = 289.6875

For the second situation, also we will apply the conservation of the amount of movement:

$515*7.5-289.6875*6 = (515+289.6875)*V$

and we have as a result:

V = 2.64 (it is moving to the right)

6 0

3 years ago

LOOK AT THE PICTURES 2!

Nadusha1986 [10]

E = 0.5mv^2 = 0.5*44*10^2 = 2200J

5 0

4 years ago

Read 2 more answers

A speeding motorist traveling with velocity Vm is spotted by a police car. The police car is initially at rest, but the instant

Svetlanka [38]

Answer:

Explanation:

Given

Let us suppose police car and motorist travel in straight line and police car catches motorist after s distance

Distance travel by motorist

$s=v_mt$ ----1

Distance traveled by Police car

$s=ut+\frac{at^2}{2}$

$s=0+\frac{a_pt^2}{2}$

$s=\frac{a_pt^2}{2}$ ----2

from 1 & 2 we get

$t=\frac{2v_m}{a_p}$

(a)Velocity of Police car after t sec

$v=u+a_pt$

$v=0+a_p\times \frac{2v_m}{a_p}$

$v=2v_m$

(b)time taken by police car is

$t=\frac{2v_m}{a_p}$

(c)Distance travel by police car $=\frac{2v_m^2}{a_p}$

7 0

3 years ago

A piece of amber is charged by rubbing with a piece of fur. If the net excess charge on the fur is +8.0 nC (+8.0 10-9 C), how ma

Ann [662]

Answer:

Number of electron on the fur will be $5\times 10^{10}electron$

Explanation:

We have given net charge on the fur $q=8nC=8\times 10^{-9}C$

Charge on one electron $e=1.6\times 10^{-19}C$

Let there are n number of electrons

So $ne=8\times 10^{-9}$

$n\times 1.6\times 10^{-19}=8\times 10^{-9}$

$n=5\times 10^{10}electron$

So number of electron on the fur will be $5\times 10^{10}electron$

6 0

3 years ago