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3 years ago

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Balance each of the following chemical equations

1 answer:

Rus_ich [418]3 years ago

8 0

Answer:

Ca+2HNO3=Ca(NO3)2+H2

Explanation:

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He standard reduction potentials of lithium metal and chlorine gas are as follows: reaction reduction potential (v) li+(aq)+e−→l

AURORKA [14]

2 Li(s) +Cl₂→ 2 Li⁺ (aq) + 2Cl⁻ (aq)

The cell potential of the reaction above is +4.40V

<em><u>calculation</u></em>

Cell potential =∈° red - ∈° oxidation

in reaction above Li is oxidized from oxidation state 0 to +1 therefore the∈° oxid = -3.04

Cl is reduce from oxidation state 0 to -1 therefore the ∈°red = +1.36 V

cell potential is therefore = +1.36 v -- 3.04 = + 4.40 V

3 0

3 years ago

According to Hund's rule of maximum spin multiplicity, how many singly-occupied orbitals are there in the valence shells of the

leva [86]

Answer:

A) carbon - 2

B) cobalt - 3

C) sulfur - 2

D) fluorine - 1

E) titanium - 2

F) germanium - 2

Explanation:

Hund's rule of maximum multiplicity:-

Firstly, every orbital which is present in the sublevel is singly occupied and then the orbital is doubly occupied.

(A) Carbon.

The electronic configuration is -

$1s^22s^22p^2$

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, Carbon has 2 singly occupied orbitals.

(B) Cobalt.

The electronic configuration is -

$1s^22s^22p^63s^23p^63d^{7}4s^2$

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 4 electrons will be paired in 2 orbitals and 3 orbitals will be singly filled in cobalt.

(C) Sulfur.

The electronic configuration is -

$1s^22s^22p^63s^23p^4$

Thus, 3s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 2 electrons will be paired in 1 orbital and 2 orbitals will be singly filled in sulfur.

D) fluorine

The electronic configuration is -

$1s^22s^22p^5$

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 4 electrons will be paired in 2 orbitals and 1 orbital will be singly filled in fluorine.

E) Titanium

The electronic configuration is -

$1s^22s^22p^63s^23p^63d^{2}4s^2$

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 2 orbitals will be singly filled in titanium.

F) Germanium

The electronic configuration is -

$1s^22s^22p^63s^23p^63d^{10}4s^24p^2$

Thus, 4s, 3d orbitals are fully filled and p orbital can singly filled 3 electrons. Thus, Germanium has 2 singly occupied orbitals.

4 0

3 years ago

Help please :<<br> I just need the answer for this as quickly as possible.

11Alexandr11 [23.1K]

Answer:

I think its the 3th one

Explanation:

8 0

3 years ago

Read 2 more answers

Which is an example of a covalent bond? Chlorine accepts an electron from calcium to form a stable bond. Ions in a bar of pure i

Ivenika [448]

Chlorine + Calcium --> Ionic Bond
Iron cannot covalently bond as it is a metal

4 0

4 years ago

Read 2 more answers

A 1.0 mol sample of which of the following compounds has the greatest mass?

Sholpan [36]

Answer:

D) N2O5

Explanation:

The molar mass of a substance is defined as the mass of this substance in 1 mol. To solve this question we must find the molar mass of each option:

<em>Molar mass NO:</em>

1N = 14g/mol*1

1O = 16g/mol*1

14+16 = 30g/mol

<em>Molar mass NO2:</em>

1N = 14g/mol*1

2O = 16g/mol*2

14+32 = 46g/mol

<em>Molar mass N2O:</em>

2N = 14g/mol*2

1O = 16g/mol*1

28+16 = 44g/mol

<em>Molar mass N2O5:</em>

2N = 14g/mol*2

5O = 16g/mol*5

28+80 = 108g/mol

That means the compound with the greatest mass is:

<h3>D) N2O5</h3>

5 0

3 years ago