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lana [24]
3 years ago
8

Two long cylinders of radii 5 cm and 10 cm form a coaxial cylindrical capacitor, the space between them being filled with a diel

ectric of relative permittivity 6. The inner cylinder carries a charge of 10-8 C m-1 of its length. Calculate:-
(a) the value of the electric displacement, field strength, and the polarisation at a

point mid-way between the plates;

(b) the potential difference between the plates;

(c) the densities of the surface charges of the dielectric;

(d) the energy associated with the dielectric in one metre of the capacitor.
Physics
1 answer:
V125BC [204]3 years ago
8 0

Answer:

21

Explanation:

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Answer:

it increases

Explanation:

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3 years ago
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The cycle that moves an important non carbon element, which organisms use to build their cells through Earth's sphere's, is the
Andrew [12]
D. Carbon

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8 0
3 years ago
Three masses are located in the x- y plane as follows: a mass of 6 kg is at (0 m, 0 m), a mass of 4 kg is at (3 m, 0 m), and a m
enot [183]

Answer:

The center of mass of three mass in the x-y plane is located at (1,0.5).                  

Explanation:

It is given that, a mass of 6 kg is at (0,0), a mass of 4 kg is at (3,0), and a mass of 2 kg is at (0,3). We need to find the center of mass of the system. Center of mass in x direction  is :

C_x=\dfrac{6\times 0+4\times 3+2\times 0}{6+4+2}\\\\C_x=1

The center of mass in y direction is :

C_y=\dfrac{6\times 0+4\times 0+2\times 3}{6+4+2}\\\\C_y=0.5

So, the center of mass of three mass in the x-y plane is located at (1,0.5).

3 0
3 years ago
The stone falls a further 25 m in the next 1.0 s of its fall. Calculate the stone's average speed during the 3 s of its fall.​
Angelina_Jolie [31]

Answer:

5 minutes sweetheart

Explanation:

thank me later-also give me brainless if you want too when you get the answer correct!

6 0
2 years ago
4. How much force is required to stop a 60 kg person traveling at 30 m/s during a time of a)
11111nata11111 [884]

Explanation:

F = ma, and a = Δv / Δt.

F = m Δv / Δt

Given: m = 60 kg and Δv = -30 m/s.

a) Δt = 5.0 s

F = (60 kg) (-30 m/s) / (5.0 s)

F = -360 N

b) Δt = 0.50 s

F = (60 kg) (-30 m/s) / (0.50 s)

F = -3600 N

c) Δt = 0.05 s

F = (60 kg) (-30 m/s) / (0.05 s)

F = -36000 N

3 0
3 years ago
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