HURRYYYY PLEASE HELP!!!

The hydrogens and oxygen of a water molecule are held together by ______ bonds. select all that apply.

zavuch27 [327]

The hydrogens and oxygen of a water molecule are held together by covalent bonds.

<h3>What are covalent bonds?</h3>

A covalent bond is an electron exchange that causes the production of electron pairs between atoms. Covalent bonding is a stable equilibrium of the attractive and repulsive forces between two atoms that occurs when they share electrons.

Bonding pairs or sharing pairs are other names for these electron pairs. Because electrons are shared among several molecules, each atom can reach the equivalent of a full valence shell, resulting in a stable electronic state.

In organic chemistry, covalent bonds are much more common than ionic bonds. Covalent bonds unite the atoms in a single water molecule, whereas hydrogen bonds join two water molecules. Water develops a covalent bond when oxygen shares an electron with each hydrogen atom.

To know more about covalent bonds, refer:

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8 0

1 year ago

A chemistry student needs 55.0g of carbon tetrachloride for an experiment. by consulting the crc handbook of chemistry and physi

Monica [59]

The volume of a substance is simply the ratio of mass and density. Therefore:

volume = mass / density

Calculating for volume of Carbon Tetrachloride that the student has to pour out:

volume = 55.0 g / (1.59 g / cm^3)

<span>volume = 34.60 cm^3</span>

6 0

3 years ago

Copper is formed when aluminum reacts with copper (II) sulfate in a single-replacement reaction. How many moles of copper can be

serg [7]

Answer:

The answer to your question is the limiting reactant is CuSO₄ and 0.975 moles of Cu were obtained

Explanation:

moles of Copper = ?

mass of Aluminum = 29 g

mass of CuSO₄ = 156 g

Limiting reactant = ?

Balanced Chemical reaction

3 CuSO₄ + 2 Al ⇒ 3 Cu + Al₂(SO₄)₃

Calculate the moles of reactants

CuSO₄ = 64 + 32 + (16 x 4) = 160g

Al = 27 g

160 g of CuSO₄ ----------------- 1 mol

156 g ----------------- x

x = (156 x 1) / 160

x = 0.975 moles

27 g of Al -------------------------- 1 mol

29 g of Al -------------------------- x

x = (29 x 1)/27

x = 1.07 moles

Calculate proportions to find the limiting reactant

Theoretical 3 moles CuSO₄/2 moles Al = 1.5 moles

Experimental 0.975 moles CuSO₄/1.07 moles = 0.91

The experimental proportion was lower than the theoretical proportion that means that the limiting reactant is CuSO₄.

3 moles of CuSO₄ ------------------ 3 moles of Cu

0.975 moles of CuSO₄ --------------- x

x = (0.975 x 3)/3

x = 0.975 moles of Cu were obtained.

3 0

3 years ago

Read 2 more answers

When testing for hydrogen gas in the laboratory a glowing splint is inserted into the gas which results in a pop sound. What is

Advocard [28]

C. Exothermic reaction I guess

5 0

2 years ago

Using the standard reduction potentials, Pb 2+(aq) + 2e– => Pb(s), E° = –0.13 V Fe 2+(aq) + 2e– => Fe(s), E° = –0.44 V Zn

mojhsa [17]

Answer:

Pb(s), Fe(s) and Zn(s) will reduce $Mn^{3+}$ to $Mn^{2+}$

Fe(s) and Zn(s) will reduce $Cr^{3+}$ to $Cr$

Explanation:

Standard reduction potential denotes ability to consume electrons from another species.

Hence, higher the standard reduction potential, higher will be the ability to oxidize another species.

Metal with $E_{red}^{0}$ value lower than 1.51 V will donate electron to $Mn^{3+}$ and thus reduces $Mn^{3+}$ to $Mn^{2+}$ .

So, Pb(s), Fe(s) and Zn(s) will reduce $Mn^{3+}$ to $Mn^{2+}$ .

Metal with $E_{red}^{0}$ value lower than -0.40 V will donate electron to $Cr^{3+}$ and thus reduces $Cr^{3+}$ to $Cr$ .

So, Fe(s) and Zn(s) will reduce $Cr^{3+}$ to $Cr$ .

6 0

3 years ago