At STP 32 g of O₂ would occupy by the same volume as 4 g of He
<h3>Further explanation</h3>
Complete question
At STP 32 g of O₂ would occupy by the same volume as:
- 4.0 g of He
- 8.0 g of CH₄
- 64 g of H₂
- 32 g of SO₂
Standard Conditions
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
So the gas will have the same volume if the number of moles is the same
mol of 32 grams of O₂ :
<em>So mol of 4 g He = mol of 32 g O₂</em>
Answer:
Electrostatic Van de Waals forces act between molecules to form weak bonds. The types of Van der Waals forces, strongest to weakest, are dipole-dipole forces, dipole-induced dipole forces and the London dispersion forces. The hydrogen bond is based on a type of dipole-dipole force that is especially powerful. These forces help determine the physical characteristics of materials.
Answer:
1 mole of Al2O3 = 102 grams
1 mole of Al2 = 54 grams
102 grams of Al2O3 contains = 54 gram of Al2
10kg of Al2O3 contains = (54/102)*10000g Al2
= 5294.11 g Al2 or 5.29411 kg
The nitrogen has been reduced or has undergone reduction and it has gained one electron
Answer:
i also had this question:P
Explanation:
