Answer:
The final state of the substance is a gas.
The sample is initially a liquid. One or more phase changes will occur.
Explanation:
Let's consider the phase diagram for Argon (not to scale).
<em>A sample of argon is initially at a pressure of 49.6 atm and a temperature of 101.4 K. The pressure on the sample is reduced to 0.680 atm at a constant temperature of 101.4 K. Which of the following are true? Choose all that apply </em>
<em>The final state of the substance is a gas.</em> TRUE. At 0.680 atm and 101.4 K, the substance is a gas.
<em>The gas initially present will solidify.</em> FALSE. Initially, Ar is present as a liquid.
<em>The final state of the substance is a solid.</em> FALSE.
<em>The sample is initially a liquid. One or more phase changes will occur.</em> TRUE. The sample is initially liquid and only one phase change will occur.
Answer:
83.9g of sulfuric acid is the minimum mass you would need
1.73g of hydrogen would be produced
Explanation:
Based on the reaction:
2 Al(s) + 3 H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 3 H₂(g)
2 moles of solid aluminium react with 3 moles of sulfuric acid. Also, two moles of Al produce 3 moles of hydrogen gas.
15.4g of Al are:
15.4g Al × (1mol / 26.98g) = 0.571 moles of Al.
Moles of sulfuric acid:
0.571 moles Al × (3 mol H₂SO₄ / 2 mol Al) = 0.8565 moles H₂SO₄
In grams:
0.8565 moles H₂SO₄ × (98g / 1mol) = <em>83.9g of sulfuric acid is the minimum mass you would need</em>
In the same way, moles of hydrogen produced are:
0.571 moles Al × (3 mol H₂ / 2 mol Al) = 0.8565 moles H₂
In grams:
0.8565 moles H₂ × (2.015g / 1mol) = <em>1.73g of hydrogen would be produced</em>
Okay so i think to calculate volume change you use the ideal gas law . this is pressure x volume = amount of substance x ideal gas constant x temperature. i honestly don’t know where to go from there but i hope this helped a bit :(
Answer:
The answer to your question is 58.7 g of Ca(OH)₂
Explanation:
Data
mass of Ca(OH)₂ = ?
mass of HNO₃ = 100 g
Process
1.- Write the balanced chemical reaction
Ca(OH)₂ + 2HNO₃ ⇒ Ca(NO₃)₂ + 2H₂O
2.- Calculate the molar mass of the reactants
Ca(OH)₂ = 40 + 32 + 2 = 74 g
HNO₃ = 1 + 14 + 48 = 63 g
3.- Use proportions to calculate the mass of Ca(OH)₂
74 g of Ca(OH)₂ ----------------- 2(63) g of HNO₃
x ----------------- 100 g of HNO₃
x = (100 x 74) / 2(63)
x = 7400 / 126
x = 58.7 g
