PbO2 (s) + 4 HCl (aq) → PbCl2 (s) + Cl2 (g) + 2 H2O (l)
This is an oxidation-reduction (redox) reaction:
PbIV + 2 e- → PbII
(reduction)
2 Cl-I - 2 e- → 2 Cl0
(oxidation)
PbO2 is an oxidizing agent, HCl is a reducing agent.
Basically, this problem tells you to convert micrometers (μm) to millimeters (mm). The prefixes are used as hints for their values. Micrometer is 10⁻⁶ of a meter, while millimeter is 10⁻³ of a meter. If you use dimensional analysis,
(1.430×10⁻³ μm)*(10⁻⁶ m/1 μm)*(1 mm/10⁻³ m) = 1.43×10⁻⁶ mm
The value of Kc for the equilibrium is 0.150 mole² / litre ²
<u>Explanation:</u>
<u>Given:</u>
An equilibrium mixture in an 1.00 L vessel contains 5.30 moles of
Mg(OH )₂ 0.800 moles of Mg²⁺ and 0.0010 moles OH₋
We have to find the value of Kc
- Step 1: Find the equilibrium Concentration.
- Step 2: Substitute the values in the equation.
- Step 3: Find the value of Kc.
- I have attached the document for the detailed explanation
The value of Kc for the equilibrium is 0.150 mole² / litre ²
ecological. i hope this helps!!!!