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charle [14.2K]
3 years ago
13

Consider the reaction: Mg(OH)₂ (s) ⇌ Mg²⁺ (aq) + 2 OH⁻ (aq)

Chemistry
1 answer:
balandron [24]3 years ago
8 0

The value of Kc for the equilibrium is 0.150 mole² / litre ²

<u>Explanation:</u>

<u>Given:</u>

An equilibrium mixture in an 1.00 L vessel contains 5.30 moles of  

Mg(OH )₂  0.800 moles of Mg²⁺ and 0.0010 moles OH₋  

We have to find the value of Kc

  • Step 1: Find  the equilibrium Concentration.
  • Step 2: Substitute the values in the equation.
  • Step 3: Find the value of Kc.
  • I have attached the document for the detailed explanation

The value of Kc for the equilibrium is 0.150 mole² / litre ²

Download pdf
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Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.
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The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

<h3>Balanced equation </h3>

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From the balanced equation above,

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MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

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2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

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