Answer:
At end point there will a transition from pink to colorless.
Explanation:
As the student put the vinegar in the titrator and NaOH in the beaker, it means that he has poured phenolphthalein in the NaOH solution.
The pH range of phenolphthalein is 8.3-10 (approx), it means it will show pink color in basic medium.
So on addition of phenolphthalein in NaOH the solution will become pink in color.
When we start pouring vinegar from titrator neutralization of NaOH will begin.
On complete neutralization , on addition of single drop of vinegar the solution will become acidic and there will be complete disappearance of pink color solution in the beaker.
C because first comes the source or producer than the first eater then the second and then it decomposes
the answer to your question is A
The correct answer is 0.06857 moles.
C₆H₁₂O₆, that is, glucose has six carbons, twelve hydrogens, and six oxygen atoms. The atomic weight of C, H and O are as follows:
Six atoms of carbon = 6 × 12.01 g = 72.06 g
Twelve atoms of hydrogen = 12 × 1.008 g = 12.096 g
Six atoms of oxygen = 6 × 16.00 g = 96.00 g
So, the molar mass of C₆H₁₂O₆ is 72.06 g + 12.096 g + 96.0 g = 180.156 g.
It can also be written in the form as 180.16 g of C₆H₁₂O₆ is equal to 1 mole of C₆H₁₂O₆or 180.16 g/mole (as the molar mass)
Now, there is a need to find moles of 12.354 grams of C₆H₁₂O₆. So, the final conversion is:
12.354 g C₆H₁₂O₆ × 1 mole of C₆H₁₂O₆ / 180.16 g C₆H₁₂O₆
= 0.06857 moles
Lithium Arsenate - Li3AsO4 (160g/mol). So, it’s 2,13 mol * 160 g/mol = 340,8 g.
