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Pani-rosa [81]
3 years ago
5

The specific heat of mercury is 380 j/kg/k. How much energy is required to raise the temperature of 42g of mercury from 25°C to

39°C?
please show work and or explain
Thanks in advance!! ​
Chemistry
1 answer:
erma4kov [3.2K]3 years ago
7 0

Answer:

Q = m c T

c= 0.140 j/(g x °c)

m= 250.0g

T =52

hope you can solve it now

Explanation:

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A 603.0 g/hr stream of liquid methyl alcohol, also called methanol, (CH3OH) at 8.10 atm and 26.0°C was held at constant pressure
mafiozo [28]

Answer:

Q=\frac{1385270 J}{hr}

Explanation:

Methanol's molecular weight: M=32 g/mol

Methanol's heat of vaporization: \Delta H_{vap}=69.69 kJ/mol

Ideal gas heat capacity (Cp):

Cp=\frac{5}{2}*R where R is the gas constant

Cp=\frac{5}{2}*8.314 \frac{J}{mol*C}=20.78\frac{J}{mol*C}

The heat needed to vaporize and bring the gs to 210°C is:

Q=\frac{603 g/hr}{32 g/mol}*(69690\frac{J}{mol}+20.78\frac{J}{mol*C}*(210-26)C)

Q=\frac{1385270 J}{hr}

4 0
3 years ago
What 2 things do the planets need to have in order to stay in orbit and rotate?
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Two things plants need to have in order to stay in orbit and rotate is speed and less velocity.
5 0
3 years ago
Choose the appropriate electron configuration for an element whose third shell contains six electrons.​
slamgirl [31]

For an element whose third shell contains six electrons, the appropriate electron configuration is; 1s2 2s2 2p6 3s2 3p4.

The electron configuration shows the distribution of electrons in the shells of an atom and in orbitals.

We have been told that the six electrons are found in the third shell. This shell has n=3 and the configuration of this shell must ns2 np4.

The only electron configuration that meets this standard is 1s2 2s2 2p6 3s2 3p4.

Learn more: brainly.com/question/18704022

5 0
3 years ago
Calculate the hydroxide ion consentration of a solution with pH = 3.25. show all calculations leading to your answer.
lidiya [134]
First you calculate the pOH of the solution:

pH+ pOH = 14

3.25 + pOH = 14

pOH = 14 - 3.25

pOH = 10.75

<span>Concentration of [OH]</span>⁻<span> in solution:
</span>
[ OH⁻ ] = 10 ^{-pOH}

[ OH⁻ ]  = 10^ - 10.75

[OH⁻] = 1.778 x 10⁻¹¹ M

hope this helps !


6 0
3 years ago
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