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Pani-rosa [81]
3 years ago
5

The specific heat of mercury is 380 j/kg/k. How much energy is required to raise the temperature of 42g of mercury from 25°C to

39°C?
please show work and or explain
Thanks in advance!! ​
Chemistry
1 answer:
erma4kov [3.2K]3 years ago
7 0

Answer:

Q = m c T

c= 0.140 j/(g x °c)

m= 250.0g

T =52

hope you can solve it now

Explanation:

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in general, as the temperature increases, the solubility of gases in water ____ and the solubility of most solids in water___
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Answer:

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What is a chemical substance that cannot be broken down into another chemical substance?
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A solution is made by dissolving 0.0150 mol of HF in enough water to make 1.00 L of solution. At 26 °C, the osmotic pressure of
Alex777 [14]
Given:
M = 0.0150 mol/L HF solution
T = 26°C = 299.15 K
π = 0.449 atm

Required:
percent ionization

Solution:
First, we get the van't Hoff factor using this equation:
π = i MRT
0.449 atm = i (0.0150 mol/L) (0.08206 L atm / mol K) (299.15 K)
i = 1.219367

Next, calculate the concentration of the ions and the acid.
We let x = [H+] = [F-]
[HF] = 0.0150 - x

Adding all the concentration and equating to iM
x +x + 0.0150 - x = <span>1.219367 (0.0150)
x = 3.2905 x 10^-3

percent dissociation = (x/M) (100) = (3.2905 x 10-3/0.0150) (100) = 21.94%

Also,
percent dissociation = (i -1) (100) = (</span><span>1.219367 * 1) (100) = 21.94%</span>
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