Question

How many milligrams of CO exist in 12000 liters of air with 10 ppm of CO?

Answer 1

Answer:

The mass of CO in 12,000 Liters of air is $12\times 10^4 mg$.

Explanation:

The ppm is the amount of solute (in milligrams) present in one Liter of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

$\text{ppm}=\frac{\text{Mass of solute}(mg)}{\text{Volume of solution}(L)}$

The ppm concentration of CO = 10 ppm

Mass of CO = m

Volume of air = 12,000 L

$10 =\frac{m}{12,000 L}$

$m=10\times 12,000 mg=120,000 mg=12\times 10^4 mg$

The mass of CO in 12,000 Liters of air is $12\times 10^4 mg$.